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mash [69]
3 years ago
15

1(whole number) 4/6 (fraction) + 2(Whole number) 1/4 (fraction)

Mathematics
2 answers:
ivanzaharov [21]3 years ago
5 0

Answer:

Step-by-step explanation:

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lbvjy [14]3 years ago
4 0

Answer:

answer is 3 11/12

Step-by-step explanation:

1 4/6 =10/6

2 1/4=9/4

when adding fractions that are do not share a common denominatour you have to find a common multiple

which in this case is 12

so 9/4 timesed the top and the bottom by 3 gives you 27/12

and 10/6 timesed the top and bottom by 2 gives you 20/12 and then you add the the nominators which is 20+27 which then gives you 47/12 and then to change it back to mixed fraction you will get 3 (wholes) and 11/12 (fraction)

Hope this helps xx

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Answer:

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Step-by-step explanation:

La medida del polígono que es igual al radio de la circunferencia es el segmento de recta comprendido entre el centro geométrico del polígono y cualquiera de sus vértices, cuyo nombre es también <em>radio</em>.

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Sphinxa [80]

Answer:

34.87% probability that all 5 have a wireless device

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

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And p is the probability of X happening.

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This means that p = 0.81

If 5 students are selected at random, what is the probability that all 5 have a wireless device?

This is P(X = 5) when n = 5. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.81)^{5}.(0.19)^{0} = 0.3487

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Answer:

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Step-by-step explanation:

In order for there to be an infinite number of solutions, the two lines need to be the same.

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