The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
</u>
Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
Answer:
Option C.
Step-by-step explanation:
It is given that the dilation rule is
. It means the center of dilatation is point Q and scale factor is 2.5.
Scale factor is the ratio of distance from center to the image of a point and distance from center to the corresponding point.

It is given that QU=4 and scale factor = 2.5.

Multiply both sides by 4.


We know that



The distance between U' and U is 6 units.
Therefore, the correct option is C.
Im guessing you meant improper. This means that the numerator is greater than the denominator. An example is 11/4
64-128-256
each step double previous number