Answer:
I am will take 20 years to get 20$
My friend will take 10 years to get 20$
Step-by-step explanation:

I hope this is be good for you and I want this money
Answer:
Here is your answer in picture...
Answer:
B 10.8 or
A 9.2 depending on what side of the triangle is "x".
Step-by-step explanation:
we cannot see the triangle and which side is which. you forgot to show us the picture (or describe it in more detail).
but I assume that "x" would be the Hypotenuse (the baseline of the right triangle, the side opposite of the 90 degree angle).
then by using Pythagoras
c² = a² + b²
=>
x² = 10² + 4² = 116
x = sqrt(116) = 10.8
but if x is any of the other sides (and not the Hypotenuse), then you need to adapt the calculation.
for example, if the Hypotenuse is the side with 10, then Pythagoras' formula would look like this
10² = x² + 4²
x² = 10² - 4² = 84
x = sqrt(84) = 9.2 (and answer A would be correct).
or if the Hypotenuse is the side with 4, then
4² = x² + 10²
x² = 4² - 10² = -84
x = sqrt(-84)
and that did not make any sense for real distances. so, this configuration is actually impossible for a right triangle.
Answer:


Step-by-step explanation:
<u>Trigonometric Ratios
</u>
The ratios of the sides of a right triangle are called trigonometric ratios.
The longest side of the right triangle is called the hypotenuse and the other two sides are the legs.
Selecting any of the acute angles as a reference, it has an adjacent side and an opposite side. The trigonometric ratios are defined upon those sides.
The image provided shows a right triangle whose hypotenuse is given. We are required to find the value of both legs.
Let's pick the angle of 30°. Its adjacent side is y. We can use the cosine ration, which is defined as follows:


Solving for y:

Since:


Simplifying:

Now we use the sine ratio:


Solving for x:

Since:


Simplifying:

The choices are not clear, but it seems like the correct answer is C.


Answer:

Step-by-step explanation:
#We use the base diagonal and the height diagonal to calculate the beam's height:

#The volume of the beam can then be calculated as:

Hence, the beam's volume is 