3 years ago

What is the slope of the line passing through (-3, 5) and (5, -3)?

Mathematics

1 answer:

Jlenok [28]3 years ago

7 0

5--3/-3-5 = -1
slope equals -1

You might be interested in

(2x + 4) — (-x + 5)<br> PLEASE HELP

Anvisha [2.4K]

(2x + 4) - (-x + 5)
= (2x + 4) -1(-x + 5)
= 2x + 4 + x - 5
= 2x + x + 4 - 5
= 3x - 1.

6 0

2 years ago

if you reflect fgh across the y-axis, what will be the coordinates of the vertices of the image f'g'h'

k0ka [10]

When you reflect FGH across the y-axis, you are left with the vertices of F'G'H at (2, -1) (-2, 2) (-4, -3)
The correct answer is b.

Hope this helps =)

6 0

3 years ago

Read 2 more answers

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

iris [78.8K]

Answer:

t = 15.42 s

Step-by-step explanation:

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation.

$y=-16x^2+242x+73$

We ned to find the time when the rocket will the ground. For this, y = 0

$-16x^2+242x+73=0$

It is a quadratic equation whose solution is given by :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 242 and c = 73

$x=\dfrac{-b+ \sqrt{b^2-4ac} }{2a}, x=\dfrac{-b-\sqrt{b^2-4ac} }{2a}\\\\x=\dfrac{-242+ \sqrt{(242)^2-4(-16)(73)} }{2(-16)}, x=\dfrac{-242- \sqrt{(242)^2-4(-16)(73)} }{2(-16)}\\\\=-0.295\ s, 15.42\ s$

Neglecting negative value.

So, it will hit the ground in 15.42 s.

5 0

2 years ago

Please help with number 10 please

lozanna [386]

Dunno what that symbol is lel

6 0

2 years ago

Cuál enunciado No es verdadero con respecto al valor de la varieble n en la siguiente ecuación?

aliina [53]

Answer:

es la c

Step-by-step explanation:

Explicación paso a paso:ya que para que de 0 tiene que ser un número negativo, tiene que ser el número inverso a 2/3, entonces n= -2/3 que tiene el mismo valor absoluto que 2/3

3 0

2 years ago