1/5, 3/5, 7/8 is from least to greatest.
Let's buils the intersection plane:
Point P is on AB and AP=2, then PB=3; point Q is on AE and AQ=1, then QE=4. Let P' be a point on CD such that CP'=2 and Q' be a point on the plane CDHG such that P'Q'=1 and P'Q' is perpendicular to CD. The line CQ' intersects HD at point R and the plane CPQR is intersection plane.
Consider triangles ΔCDR and ΔCP'Q', they are similar. So,

,
so R is a midlepoint of the side HD (for details see picture).
Answer:
x=2
ab=7
bc=5
Step-by-step explanation:
because you do
2x+3 = 4x+3
-3 -3
2x=4x
-2x -2x
x = 2
2x2+3
4+3
=7
4x2-3
8-3
=5
Answer:
the answer is point f. mostly the answer of such type of questions are the points which do not lie ON the circle