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Serjik [45]
3 years ago
8

What is the surface area of the cylinder with height 8 ft and radius 5 ft? Round your answer to the nearest thousandth.

Mathematics
1 answer:
m_a_m_a [10]3 years ago
3 0
A≈408.41ft² < that is the answer
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–6 &lt; 2x – 4 &lt; 4 solve the inequality
Ira Lisetskai [31]

Answer:

The answer is

<h2>- 1 < x < 4</h2>

Step-by-step explanation:

<h3>- 6 < 2x - 4 < 4</h3>

First of all add 4 to both sides of the inequality to make 2x stand alone

That's

<h3>- 6 + 4 < 2x - 4 + 4 < 4 + 4 \\  - 2 < 2x < 8</h3>

Divide both sides of the inequality by 2 inorder to find x

That's

<h3>\frac{ - 2}{2}  <  \frac{2x}{2}  <  \frac{8}{2}</h3>

We have the final answer as

<h3>- 1 < x < 4</h3>

Hope this helps you

6 0
3 years ago
What’s the answer to #12? and why
Elena L [17]
Remark
If there are 5 distinct zeros that means either that the x axis is crossed the x axis 5 different places or touched the x axis in 1 place out the 5. Touching in one place means that an even number of roots are the same. 

So let's go through all of them to get an answer of 5.

A has 4 x intercepts. It is not the right answer. We need 5.
B has 4 x intercepts. It is not the right answer. We need 5.
C has 6 x intercepts. Not the one we want.
D has 5 x distinct zeros. The wording is a bit tricky. It does not matter than one of them just touches the x axis. There could be an even number of distinct zeros there, but it only counts as one root.

An example of such a graph is f(x)=\left(\frac{1}{10}(x+2)(x+1.5)(x+1)(x-2)^4(x-3)\right)
 
Answer D <<<<<


6 0
3 years ago
Read 2 more answers
The question has a period I don’t know why
Xelga [282]
It is not a question it’s telling you to do it haha! But just divide the (hours of / days) for example 7/2 and that would be your answer!
7 0
3 years ago
Fill in the graphic organizer by writing the example of way to regroup
skad [1K]
You could make circle like apples until you get all of them I hope this is right
8 0
3 years ago
(x^2 - x^(1/2))/(1-x^(1/2))
Levart [38]
\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 }  } \right)  }{ \left( 1-{ x }^{ \frac { 1 }{ 2 }  } \right)  }

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot 1

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot \frac { \left( 1+\sqrt { x }  \right)  }{ \left( 1+\sqrt { x }  \right)  }

\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }

\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\}  }{ \left( 1-x \right)  }

\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }\left( 1+{ x }^{ \frac { 2 }{ 2 }  } \right) -x

\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }-{ x }^{ \frac { 3 }{ 2 }  }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x
3 0
3 years ago
Read 2 more answers
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