Question

The acid ionization equilibrium for the weak acid HF is represented by the equation above. To prepare a buffer with a pH=3.50, a student needs to mix 250.mL of 0.100MHF and 250.mL of 0.100MKF. If the student mistakenly mixes 250.mL of 0.0500MHF and 250.mL of 0.0500MKF, which of the following is the result of this error?
The buffer will have a lower capacity because of the smaller number of moles of HF and F− available to react if an acid or base is added.

The buffer will have a lower capacity because of the smaller number of moles of H F and F with a negative 1 charge available to react if an acid or base is added.


The buffer will have a lower capacity because the smaller amount of HF and F− will lower the pH of the buffer, and buffers of lower pH have a lower buffer capacity.

The buffer will have a lower capacity because the smaller amount of H F and F with a negative 1 charge will lower the p H of the buffer, and buffers of lower p H have a lower buffer capacity.


The buffer will have a higher capacity because a larger proportion of HF and F− will ionize at lower concentrations, resulting in the neutralization of any added acid or base.

The buffer will have a higher capacity because a larger proportion of H F and F with a negative 1 charge will ionize at lower concentrations, resulting in the neutralization of any added acid or base.


The buffer will have the same capacity because the large volume of the buffer solution dilutes any added acid or base

Answer 1

Answer:

4

Explanation: