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Sidana [21]
3 years ago
8

What is the molarity of a 50.0 mL solution that contains 0.0350 mol of sodium sulfate, Na2SO4?

Chemistry
1 answer:
Ymorist [56]3 years ago
3 0

Answer:

The molarity of a 50.0 mL solution that contains 0.0350 mol of sodium sulfate 0.7 \frac{moles}{liter}

Explanation:

Molarity is a concentration measure that indicates the amount of moles of solute that appear dissolved in each liter of the mixture.

So, the Molarity of a solution is determined by the expression:

Molarity (M)=\frac{number of moles of solute}{volume}

Molarity is expressed in units (\frac{moles}{liter}).

In this case:

  • number of moles= 0.0350
  • Volume=50 mL=0.05 L (1 L= 1,000 mL)

Replacing:

Molarity=\frac{0.0350 moles}{0.05 L}

Molarity= 0.7 \frac{moles}{liter}

<u><em>The molarity of a 50.0 mL solution that contains 0.0350 mol of sodium sulfate 0.7 </em></u>\frac{moles}{liter}<u><em></em></u>

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The volume of  0. 250 mole sample of H_{2} gas occupy if it had a pressure of 1. 70 atm and a temperature of 35 °C is  3.71 L.

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According to ideal gas equation which is known as ideal gas law,

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