All categories

2 years ago

Select the physical properties. select all that apply. density hardness boiling point melting point reactivity fllammability

Chemistry

2 answers:

Crank2 years ago

7 0

Answer: Density, Hardness, Boiling point, Melting Point

Explanation: Physical Properties are those properties which can be measured. These are those observables which can be used to defined to the state of the system and which do not bring any change in the molecular composition of the system.

Whereas Chemical Properties are those which can bring changes in the original identity of the composition.

Out of the given, Density, Hardness, Boiling Point and Melting Point r the properties due to which the physical state of any system can be defined.

Reactivity and Flammability cannot be considered among them.

anzhelika [568]2 years ago

4 0

The answer to the given problem are:
1. Density
2. Hardness
3. Boiling Point
4. Melting Point

These are the list of physical properties except for two which are reactivity and flammability. These two should be excluded in the list of physical properties.

You might be interested in

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m

koban [17]

Here is the full question:

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes? (Round your answer to three decimal places.

Answer:

0.046 %

Explanation:

The rate-in;

$R_{in}$ $= \frac{0.04}{100}*2000$

$R_{in}$ = 0.8

The rate-out

$R_{out}$ = $\frac{A}{6000}*2000$

$R_{out}$ = $\frac{A}{3}$

We can say that:

$\frac{dA}{dt}=$ $0.8-\frac{A}{3}$

where;

A(0)= 0.2% × 6000

A(0)= 0.002 × 6000

A(0)= 12

$\frac{dA}{dt} +\frac{A}{3} =0.8$

Integration of the above linear equation =

$e^{\int\limits \frac {1}{3}dt } =$ $e^{\frac{1}{3}t$

so we have:

$e^{\frac{1}{3}t}\frac{dA}{dt}} +\frac{1}{3}e^{\frac{1}{3}t}A$ $= 0.8e^{\frac{1}{3}t$

$\frac{d}{dt}[e^{\frac{1}{3}t}A]$ $= 0.8e^{\frac{1}{3}t$

$Ae^{\frac{1}{3}t} =2.4e\frac{1}{3}t +C$

∴ $A(t) = 2.4 +Ce^{-\frac{1}{3}t$

Since A(0) = 12

Then;

$12 =2.4 + Ce^{-\frac{1}{3}}(0)$

$C= 12-2.4$

$C =9.6$

Hence;

$A(t) = 2.4 +9.6e^{-\frac{t}{3}}$

$A(0) = 2.4 +9.6e^{-\frac{10}{3}}$

$A(t) = 2.74$

∴ the concentration at 10 minutes is ;

= $\frac{2.74}{6000}*100$ %

= 0.0456667 %

= 0.046% to three decimal places

7 0

3 years ago

An atom has three full orbitals in its second energy level.

ICE Princess25 [194]

Orbitals am only hold two electrons each, so 3 orbitals can hold 6 electrons

7 0

3 years ago

Read 2 more answers

A student placed a stack of rocks on a ramp. She added clumps of soil rooted with live grass. Using a garden hose, she then appl

Sliva [168]

<span>Answer D. Spray from the hose suggests water in liquid state falling into the soil. The process of elimination: A glacier can be related to water in frozen but in static state. B Fast winds has the element of movement of air, not water. C. A hail storm, movement of water in frozen state. D. Heavy rains looks to be better choice compares to the others.</span>

7 0

3 years ago

Read 2 more answers

Which statement is TRUE about oxidation-reduction reactions? a. Every oxidation must be accompanied by a reduction. b. There are

Tomtit [17]

Answer:

Every oxidation must be accompanied by a reduction.

Explanation:

Oxidation and reduction are complementary processes. There can be no oxidation without reduction and vice versa. It is actually a given an take affair. A specie looses electrons which must be gained by another specie to complete the process. This explains why the selected option is the correct one.

8 0

2 years ago

Each of the following names is wrong. Draw structures based on them, and correct the names:(b) 1,1,1-trimethylheptane

devlian [24]

The correct IUPAC name of 1,1,1-trimethylheptane is 2,2-dimethyloctane.

<h3>IUPAC NAME:</h3>

It is systematic way of nomenclature of organic compounds.

It is based on the position of functional groups, preference of the functional group, long or short chain of carbon, preference of double bond, single and triple bond, branching of carbon chain, etc.

The given compound is 1,1,1-trimethylheptane.

The given name is wrong according to IUPAC name because the numbering of carbon atom should be done in that way in which the carbon atom chain is largest.

Here, in this case the numbering is done from right side. Thus the largest carbon chain have 8 carbon atom.

If the numbering is done according to the question, number of carbon atom in straight chain is 7.

Thus, we concluded that the Correct IUPAC name of 1,1,1-trimethylheptane is 2,2-dimethyloctane.

learn more about Nomenclature:

brainly.com/question/14094007

#SPJ4

5 0

1 year ago