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frutty [35]
3 years ago
6

What is g(x)= 7/8(7) - 1/2

Mathematics
1 answer:
laila [671]3 years ago
7 0
Answer: g=3/56

Hope this helps you
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A regular heptagon has sides measuring 26 mm and is divided into 7 congruent triangles. Each triangle has a height of 27 mm. Wha
Inessa [10]
567 square mm
because 27*7 is 189 an times 3 because each side has 3 sides so it equals to 567 square mm! :)

8 0
2 years ago
Nia has $19.50 to ride the subway around New York. It will cost her $0.75 every time she rides. Identify the dependent variable
ra1l [238]

Answer:

The correct answer is B. The number of rides and the total cost are both dependent variables, as both depend on the amount of money that Nia has.

Step-by-step explanation:

The total cost is dependent because it relies on how many rides Nia takes, and the $19.50 limit.

The number of rides is dependent on the limit of $19.50 because the $19.50 is the limit and the total amount of rides is locked by $19.50

I'm not sure, though.

5 0
3 years ago
Read 2 more answers
Compute the permutations and combinations. From a committee consisting of 5 men and 6 women, a sub-committee is formed consistin
kolbaska11 [484]

Answer:

360

Step-by-step explanation:

Multiply them all

3 0
3 years ago
Julie has $50 to spend on meat and
amid [387]

Answer: 10y+5x=50

Step-by-step explanation: $10 times y + $5 times x =$50

6 0
2 years ago
What is the correct justification for the indicated steps?
yanalaym [24]

The given proof of De Moivre's theorem is related to the operations of

complex numbers.

<h3>The Correct Responses;</h3>
  • Step A: Laws of indices
  • Step C: Expanding and collecting like terms
  • Step D: Trigonometric formula for the cosine and sine of the sum of two numbers

<h3>Reasons that make the above selection correct;</h3>

The given proof is presented as follows;

\mathbf{\left[cos(\theta) + i \cdot sin(\theta) \right]^{k + 1}}

  • Step A: By laws of indices, we have;

\left[cos(\theta) + i \cdot sin(\theta) \right]^{k + 1} = \mathbf{\left[cos(\theta) + i \cdot sin(\theta) \right]^{k} \cdot \left[cos(\theta) + i \cdot sin(\theta) \right]}

\left[cos(\theta) + i \cdot sin(\theta) \right]^{k} \cdot \left[cos(\theta) + i \cdot sin(\theta) \right] =  \mathbf{\left[cos(k \cdot \theta) + i \cdot sin(k \cdot \theta) \right] \cdot \left[cos(\theta) + i \cdot sin(\theta) \right]}

  • Step B: By expanding, we have;

\left[cos(k \cdot \theta) + i \cdot sin(k \cdot \theta) \right] \cdot \left[cos(\theta) + i \cdot sin(\theta) \right] = cos(k \cdot \theta) \cdot cos(\theta) - sin(k \cdot \theta) \cdot sin(\theta) + i  \cdot \left [sin(k \cdot \theta) \cdot cos(\theta) + cos(k \cdot \theta) \cdot sin(\theta) \right]

  • Step D: From trigonometric addition formula, we have;

cos(A + B) = cos(A)·cos(B) - sin(A)·sin(B)

sin(A + B) = sin(A)·cos(B) + sin(B)·cos(A)

Therefore;

cos(k \cdot \theta) \cdot cos(\theta) - sin(k \cdot \theta) \cdot sin(\theta) + i  \cdot \left [sin(k \cdot \theta) \cdot cos(\theta) + cos(k \cdot \theta) \cdot sin(\theta) \right] = \mathbf{ cos(k \cdot \theta + \theta) + i \cdot sin(k \cdot \theta  + \theta)}

Learn more about  complex numbers here:

brainly.com/question/11000934

4 0
2 years ago
Read 2 more answers
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