Answer:
242
Step-by-step explanation:
7(6*6)-10
7(36)-10
252-10
=242
Answer:
3
Step-by-step explanation:
The number is 3.
Step-by-step explanation:
Finding the Number
To find the number, we have to translate the problem above to an algebraic equation. The algebraic equation refers to the statement of the equality of two algebraic expressions.
Equation:
Let "x" be the number.
4 is divided by a number - 4/x
3 divided by the number decreased by 2 - 3/x-2
"4 is divided by a number is equal to 3 divided by the number decreased by 2"
4/x = 3/x-2
Solution:
Cross multiply.
4/x = 3/x-2
x(3) = 4(x-2)
3x = 4x - 8
(Combine similar terms.)
3x - 4x = - 8
- x = - 8
- x/- 1 = - 8/- 1
x = 8
Final Answer:
8
Checking:
4/x = 3/x-2
4/8 = 3/8-2
1/2 = 3/6
1/2 = 1/2 ✔
You figure out how long it would take a car traveling at 25 mph
to cover 360 ft. Any driver who does it in less time is speeding.
(25 mi/hr) · (5,280 ft/mile) · (1 hr / 3,600 sec)
= (25 · 5280 / 3600) ft/sec = (36 and 2/3) feet per second.
To cover 360 ft at 25 mph, it would take
360 ft / (36 and 2/3 ft/sec) = 9.82 seconds .
Anybody who covers the 360 feet in less than 9.82 seconds
is moving faster than 25 mph.
_________________________________
If you're interested, here's how to do it in the other direction:
Let's say a car covers the 360 feet in ' S ' seconds.
What's the speed of the car ?
(360 ft / S sec) · (1 mile / 5280 feet) · (3600 sec/hour)
= (360 · 3600) / (S · 5280) mile/hour
= 245.5 / S miles per hour .
The teacher timed one car crossing both strips in 7.0 seconds.
How fast was that car traveling ?
245.5 / 7.0 = 35.1 miles per hour
Another teacher timed another car that took 9.82 seconds to cross
both strips. How fast was this car traveling ?
245.5 / 9.82 = 25 miles per hour
e + 1 13/16 = 2 5/16
subtract 1 13/16 from each side
e = 2 5/16 - 1 13/16
borrow from the 2
e = 1 16/16 + 5 /16 - 1 13/16
e = 1 21/16-1 13/16
e = 1 8 /16
e = 1 1/2
Answer:
See below.
Step-by-step explanation:
The domain which is all the posible values of x is: x is real and in the interval
[1, 6].
The range is real f(x) in the interval [1, 7].
