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tiny-mole [99]
2 years ago
9

Math, area all that yummy stuff

Mathematics
1 answer:
lilavasa [31]2 years ago
5 0

Answer:

If im not wrong, just multiply wxlxh, for all sides, and you get 1260.

Step-by-step explanation:

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HELP with these questions
zlopas [31]

<u>Step-by-step explanation:</u>

transform the parent graph of f(x) = ln x        into f(x) = - ln (x - 4)  by shifting the parent graph 4 units to the right and reflecting over the x-axis

(???, 0): 0 = - ln (x - 4)

            \frac{0}{-1} = \frac{-ln (x - 4)}{-1}

            0 = ln (x - 4)

            e^{0} = e^{ln (x - 4)}

             1 = x - 4

          <u> +4 </u>  <u>    +4 </u>

             5 = x

(5, 0)

(???, 1): 1 = - ln (x - 4)

            \frac{0}{-1} = \frac{-ln (x - 4)}{-1}

            1 = ln (x - 4)

            e^{1} = e^{ln (x - 4)}

             e = x - 4

          <u> +4 </u>   <u>    +4 </u>

         e + 4 = x

          6.72 = x

(6.72, 1)

Domain: x - 4 > 0

                <u>  +4 </u>  <u>+4  </u>

               x       > 4

(4, ∞)

Vertical asymptotes: there are no vertical asymptotes for the parent function and the transformation did not alter that

No vertical asymptotes

*************************************************************************

transform the parent graph of f(x) = 3ˣ        into f(x) = - 3ˣ⁺⁵  by shifting the parent graph 5 units to the left and reflecting over the x-axis

Domain: there is no restriction on x so domain is all real number

(-∞, ∞)

Range: there is a horizontal asymptote for the parent graph of y = 0 with range of y > 0.  the transformation is a reflection over the x-axis so the horizontal asymptote is the same (y = 0) but the range changed to y < 0.

(-∞, 0)

Y-intercept is when x = 0:

f(x) = - 3ˣ⁺⁵

      = - 3⁰⁺⁵

      = - 3⁵

      = -243

Horizontal Asymptote: y = 0  <em>(explanation above)</em>

5 0
3 years ago
How can I solve this problem (5^3)^-2? Can you help me
ICE Princess25 [194]
First multiply the power, 3 x -2 = -6
Thus, 5^-6
Make the power positive
1/5^6
1/15625
4 0
3 years ago
G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =
laiz [17]

Given:

The two functions are:

g(b)=5b-9

h(b)=(b-1)^2

To find:

The value of (h\circ g)(-6).

Solution:

We have,

g(b)=5b-9

h(b)=(b-1)^2

We know that,

(h\circ g)(b)=h(g(b))

(h\circ g)(b)=h(5b-9)

(h\circ g)(b)=[(5b-9)-1]^2

(h\circ g)(b)=[5b-10]^2

Putting b=-6, we get

(h\circ g)(-6)=[5(-6)-10]^2

(h\circ g)(-6)=[-39-10]^2

(h\circ g)(-6)=[-49]^2

(h\circ g)(-6)=2401

Therefore, the value of (h\circ g)(-6) is 2401.

7 0
3 years ago
Which statement explains why the value of [2.4] is 2 but the value of [-2.4] is –3?
GenaCL600 [577]
For any x in Real numbers, [x] is the greatest possible integer smaller than x, or equal to x if x is an integer.

According to this,

<span>[2.4] is the greatest integer , smaller than or equal to (so non greater) 2.4. This number is 2

similarly,  </span>[-2.4] is the greatest integer , smaller than or equal to (so non greater) -2.4. This number is -3.


Answer: 

A) <span>Because 2 is the greatest integer not greater than 2.4 and –3 is the greatest integer not greater than –2.4. </span>
3 0
3 years ago
Read 2 more answers
HigherOrder thing name two rays with the same endpoint in the figure below. Do they form an angle? Explain.
Artist 52 [7]

Answer:

where is the figure?

Step-by-step explanation:

4 0
3 years ago
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