Answer: a. 1.981 < μ < 2.18
b. Yes.
Step-by-step explanation:
A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.
First, we calculate mean of the sample:


2.08
Now, we estimate standard deviation:


s = 0.1564
For t-score, we need to determine degree of freedom and
:
df = 12 - 1
df = 11
= 1 - 0.95
α = 0.05
0.025
Then, t-score is
= 2.201
The interval will be
± 
2.08 ± 
2.08 ± 0.099
The 95% two-sided CI on the mean is 1.981 < μ < 2.18.
B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.
\left[x \right] = \left[ \frac{5\,y}{158}+\frac{6\,z}{79}\right][x]=[1585y+796z] totally answer
-10 and 8 multiply them to equal 80 but if there both negative it will be a positive 80 because if you multiply 2 negatives its postive hope this helps
Answer:
15 questions
Step-by-step explanation:
9x100=900
900/60=15
9/15=60%
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Answer:
Difference between standard score and raw score
In statistics, the standard score is the number of standard deviations by which the value of a raw score (i.e., an observed value or data point) is above or below the mean value of what is being observed or measured.
Step-by-step explanation:
normal and rare are same