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notka56 [123]
3 years ago
9

Hello can you help meee

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
7 0

Answer:

x=4\sqrt{2}

Step-by-step explanation:

The given triangle is a 45°-45°-90° triangle. Use the following rule:

leg=leg\\\\hypotenuse=leg*\sqrt{2}

The length of the legs is 4. Insert this value into the equation:

h=4*\sqrt{2}

Simplify:

h=4\sqrt{2}

:Done

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Yes

Step-by-step explanation:

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What’s y of 2x+3y=7.20 and 4x+2y=8.80
Arturiano [62]

Answer:

(x,y)=(3/2,7/5)

Step-by-step explanation:

7 0
3 years ago
Help me please!!!!!!!!
Alexxx [7]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Trig proofs with Pythagorean Identities.
lorasvet [3.4K]

To prove:

$\frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}=2 \cot ^{2} x+1

Solution:

$LHS = \frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}

Multiply first term by \frac{1+cos x}{1+cos x} and second term by \frac{1-cos x}{1-cos x}.

        $= \frac{1(1+\cos x)}{(1-\cos x)(1+\cos x)}-\frac{\cos x(1-\cos x)}{(1+\cos x)(1-\cos x)}

Using the identity: (a-b)(a+b)=(a^2-b^2)

        $= \frac{1+\cos x}{(1^2-\cos^2 x)}-\frac{\cos x-\cos^2 x}{(1^2-\cos^2 x)}

Denominators are same, you can subtract the fractions.

       $= \frac{1+\cos x-\cos x+\cos^2 x}{(1^2-\cos^2 x)}

Using the identity: 1-\cos ^{2}(x)=\sin ^{2}(x)

       $= \frac{1+\cos^2 x}{\sin^2x}

Using the identity: 1=\cos ^{2}(x)+\sin ^{2}(x)

       $=\frac{\cos ^{2}x+\cos ^{2}x+\sin ^{2}x}{\sin ^{2}x}

       $=\frac{\sin ^{2}x+2 \cos ^{2}x}{\sin ^{2}x} ------------ (1)

RHS=2 \cot ^{2} x+1

Using the identity: \cot (x)=\frac{\cos (x)}{\sin (x)}

        $=1+2\left(\frac{\cos x}{\sin x}\right)^{2}

       $=1+2\frac{\cos^{2} x}{\sin^{2} x}

       $=\frac{\sin^2 x + 2\cos^{2} x}{\sin^2 x} ------------ (2)

Equation (1) = Equation (2)

LHS = RHS

$\frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}=2 \cot ^{2} x+1

Hence proved.

5 0
3 years ago
PLEASE HELP ILL MARK YOU BRAINLIEST!!!!! 75 POINTS Use the function f(x) = 2x2 − 5x + 3 to answer the questions. Part A: Complet
andrew-mc [135]

Answer:

A. (2x-3)(x-1)

B. (1,0) \\(1.5,0)

2x^2-5x+3\\\frac{5(+ or -)\sqrt{(-5)^2-(4)(2)(3)}  }{2(2)} \\\frac{5(+ or -)\sqrt{25-24}  }{4}\\\frac{5(+ or -)\sqrt{1}  }{4}\\ \frac{5(+ or -)1  }{4}\\\frac{5+1}{4} or \frac{5-1}{4} \\ \frac{6}{4} =1.5  and \frac{4}{4} =1

C. Both sides will continue to increase as they go because this is an even degree quadratic equation.

D. You use the two x-intercepts to make sure it is in the correct area and since we know the end behavior all you'd have to assume is that it continues to go up so any negative answers you may accidentally receive would be incorrect.

3 0
3 years ago
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