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dexar [7]
3 years ago
11

Consider the following graph, which details the observed bear population in two national parks. A graph titled Bears Observed in

Park has month on the y-axis and number of bears observed on the y-axis, going from 37 to 53. In the same month, there are 2 points marked on the graph. All points are connected by overlapping lines. Of the following, which option or options would help make this graph less misleading? I. The scale on the x-axis should be resized. II. The scale on the y-axis should be resized. III. The identity of the two parks should be more clearly differentiated. a. I and II b. II and III c. III only d. I and III
ANSWER IS B
Mathematics
1 answer:
damaskus [11]3 years ago
6 0

Answer:

b. II and III

Step-by-step explanation:

A graph is a data presentation that has two axis - x and y, divided into appropriate scales.

A scale is used to divide given units into equal parts. It is crucial to and used to create uniformity in drawing of graphs. Choosing a good scale to represent an information on a graph is vital to avoid confusion. This can be done by considering the variations in the values forming the data.

In the question, the single graph shows an information about the bear population in two national parks. Thus, the scale of the y-axis must be adjusted and the identity of the two parks be more differentiated so as to make the graph less misleading.

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Answer: The solution is,

x_1\approx 0.876

x_2\approx 0.419

x_3\approx 0.574

Step-by-step explanation:

Given equations are,

8x_1 + x_2 + x_3 = 8

2x_1 + 4x_2 + x_3 = 4

x_1 + 3x_2 + 5x_3 = 5,

From the above equations,

x_1=\frac{1}{8}(8-x_2-x_3)

x_2=\frac{1}{4}(4-2x_1-x_3)

x_3=\frac{1}{5}(5-x_1-3x_2)

First approximation,

x_1(1)=\frac{1}{8}(8-(0)-(0))=1

x_2(1)=\frac{1}{4}(4-2(1)-(0))=0.5

x_3(1)=\frac{1}{5}(5-1-3(0.5))=0.5

Second approximation,

x_1(2)=\frac{1}{8}(8-(0.5)-(0.5))=0.875

x_2(2)=\frac{1}{4}(4-2(0.875)-(0.5))=0.4375

x_3(2)=\frac{1}{5}((0.875)-3(0.4375))=0.5625

Third approximation,

x_1(3)=\frac{1}{8}(8-(0.4375)-(0.5625))=0.875

x_2(3)=\frac{1}{4}(4-2(0.875)-(0.5625))=0.421875

x_3(3)=\frac{1}{5}(5-(0.875)-3(0.421875))=0.571875

Fourth approximation,

x_1(4)=\frac{1}{8}(8-(0.421875)-(0.571875))=0.875781

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x_3(4)=\frac{1}{5}(5-(0.875781)-3(0.419141))=0.573359

Fifth approximation,

x_1(5)=\frac{1}{8}(8-(0.419141)-(0.573359))=0.875938

x_2(5)=\frac{1}{4}(4-2(0.875938)-(0.573359))=0.418691

x_3(5)=\frac{1}{5}(5-(0.875938)-3(0.418691))=0.573598

Hence, by the Gauss Seidel method the solution of the given system is,

x_1\approx 0.876

x_2\approx 0.419

x_3\approx 0.574

4 0
3 years ago
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