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3 years ago

Find the value of a.

Mathematics

1 answer:

Elena-2011 [213]3 years ago

6 0

Answer: 14

Step-by-step explanation: The perimeter is all of the side added together. When finding the perimeter of a rectangle the opposing sides have the same value. So the equation would be 2(12) + 2(a) = 52. 12 x 2 is 24. 52- 24 is 28 and youre left with 28 = 2(a). You divide each side by 2 and get 14 = a

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$P(X>600)=P(\frac{X-\mu}{\sigma}>\frac{600-\mu}{\sigma})=P(Z>\frac{600-510}{14.28})=P(z>6.302)$

And we can find this probability using the complement rule and the normal standard distribution and we got:

$P(z>6.302)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the number of attacks of a population, and for this case we know the distribution for X is given by:

$X \sim N(510,14.28)$

Where $\mu=510$ and $\sigma=14.28$

We are interested on this probability

$P(X>600)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>600)=P(\frac{X-\mu}{\sigma}>\frac{600-\mu}{\sigma})=P(Z>\frac{600-510}{14.28})=P(z>6.302)$

And we can find this probability using the complement rule and the normal standard distribution and we got:

$P(z>6.302)=1-P(z$

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3 years ago