3(x^2 + 6x + 5) = 0
3(x^2 + 6x + 9 + 5 - 9) = 0
3(x + 3)^2 + 3(-4) = 0
3(x + 3)^2 - 12 = 0
3(x + 3)^2 = 12
(x + 3)^2 = 4
x + 3 = sqrt(4)
x = -3 + or - 2
x = -3 + 2 or -3 - 2
x = -1 or -5
The correct answer option is option c.
Answer:
x = -5, x = -6
Step-by-step explanation:
After canceling common terms from numerator and denominator, there are two factors remaining in the denominator that can become zero. The vertical asymptotes are at those values of x.
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The denominator will be zero when ...
x + 5 = 0 . . . . at x = -5
x + 6 = 0 . . . . at x = -6
Answer:
مرحبًا ، لا أعرف الإجابة لأنني أتحدث الإنجليزية آسف ، أنا فقط بحاجة إلى نقاط
And what I need more information to answer your question.