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3 years ago

A summer job pays $5 per hour.

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

8 0

You just need to add to get your answer

blagie [28]3 years ago

4 0

Answer:

A. 60, B. 120.

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Find f(-2) for the function f (x) = 3x^2-2x+7

barxatty [35]

Answer:

Step-by-step explanation:

plug -2 in for x then solve

4 0

3 years ago

An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the

MrRa [10]

your question is incomplete, here you can find the complete question below:

An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the varying radian measure of the angle.

a. if the terminal ray of the angle passes through the point(3.38,2.32), whta is the slope of the terminal ray of the angle?

b. if the terminal ray of the angle passes through the point(1.49,3.82), whta is the slope of the terminal ray of the angle?

c. if the terminal ray of the angle passes through the point(1.1,3.95), what is the slope of the terminal ray of the angle?

Answer:

a. 1.45

b. 2.56

c. 3.59

Step-by-step explanation:

As we know that formula to find the slope is change in y-coordinates divided by change in x-coordinates.

$slope=\frac{chnage\ in\ y}{chnage\ in\ x}=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

It is given that initial point is (x1,y1)=(0,0)

Part(a)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(3.38,2.32)

so the slope of the terminal ray is

$slope=\frac{3.38-0}{2.32-0}=\frac{3.38}{2.32}= 1.45$

Part(b)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.49,3.82)

so the slope of the terminal ray is

$slope=\frac{3.82-0}{1.49-0}=\frac{3.82}{1.49}=2.56$

Part(c)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.1,3.95)

so the slope of the terminal ray is

$slpoe=\frac{3.95-0}{1.1-0}=\frac{3.95}{1.1}= 3.59$

6 0

3 years ago

A computer takes 3x2 + 2 milliseconds to process a certain program. If the program has 4 lines of static code (this will always

matrenka [14]

Solution:

Average time per line = total time / total lines

Average time per line = (3x^2 + 2)/(x + 4)

Average time per line = 3x - 12 + (3x^2 + 2)/50 milliseconds

4 0

3 years ago

Read 2 more answers

The graph represents function 1, and the equation represents function 2:

kvv77 [185]

Answer:

Please check the explanation.

Step-by-step explanation:

We know that the slope or rate of change of the function can be:

positive

negative

zero, or

undefined

Function 1

From the function 1 graph, it is clear that the graph is a horizontal line. We must note that the horizontal line has a slope or rate of change zero. The reason is that the horizontal line can not rise vertically. i.e. y₂-y₁=0

so using the slope formula

Rate of change = m = y₂-y₁ / x₂-x₁

Taking two points (x₁, y₁) = (0, 4), (x₂, x₁) = (1, 4)

Rate of change = m = 4-4 / 1-0

Rate of change = m = 0/1

Rate of change = m = 0

Thus, the rate of change of function 1 is zero.

Function 2

We know the slope-intercept form of linear equation is

$y = mx+b$