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3 years ago

What is the arc length of the arc subtended in a circle with radius 6 and anangle of 7 8?

1 answer:

6 0

Arc length = x/360 × 22/7 × 6 × 2

x = 78

Arc length = 78/360 × 22/7 × 6 × 2

= 13/60 × 22/7 × 12

= 13/5 × 22/7

= 8.171

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Raj gave his mother a bouquet of 12 pink and white roses. There were 4 pink roses in the bouquet. Which ratio

Studentka2010 [4]

Sorry I was wrong, I didn’t mean to get it wrong.

6 0

3 years ago

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If rectangle ABCD is dilated by a scale factor of 3 with a center of dilation at vertex D, what is the perimeter of A'B'C'D?

kramer

The ans is C) 90 units

5 0

3 years ago

Find the missing length. The triangles are similar.

Marina CMI [18]

Answer:

RK= 13 SK= 12

Step-by-step explanation

First, we find the missing length of RK using the given information: 65-52=13

Then we divide 65 by 13 to get a scale factor: 65/13=5

(To check, we multipuly: 13*5=65)

We then apply the scale factor to MK to find SK: 60/5=12

(To check we multipuly: 5*12=60)

We now have our answers: RK:13, SK:12

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3 years ago

If you can please help me

finlep [7]

Answer/Step-by-step explanation:

1. -14

2. 3

3. -3

4. 10

5. -8

1. 4 x -3 = -12 - 2 = 14

2. -3 x 2 = -6 + 9 = 3

3. 8 divided by 4 = 2 - 5 = -3

4. 3/2 = 1.5 x 2 = 3 + 7 = 10

5. -9/3 = -3 - 5 = -8

3 0

3 years ago

Please can someone show me how to work this out step by step without a calculator

Artyom0805 [142]

$2\sqrt8\times8\sqrt2=(2\times8)\sqrt{8\times2}=16\sqrt{16}=16\times4=64$

Alternatively, you can write radicals as rational exponents, so that you get

$2\sqrt8\times8\sqrt2=2\tiems8^{1/2}\times8\times2^{1/2}=2^{3/2}8^{3/2}$

Then recalling that $2^3=8$ , you have

$2^{3/2}8^{3/2}=2^{3/2}(2^3)^{3/2}=2^{3/2}2^{9/2}=2^{12/2}=2^6=64$

5 0

4 years ago