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3 years ago

I WILL GIVE BRAINLIST

Mathematics

1 answer:

GrogVix [38]3 years ago

4 0

Answer:

3,406.5 litres/hr

Step-by-step explanation:

The liquid is being poured at a rate of 15 gallons per minute.

1 minute = 1/60 hour

Thus, the rate can be written as:

15 gallons pet 1/60 hour

We are told that one gallon is approximately 3.785 liters.

Thus;

15 gallons = 15 × 3.785 litres = 56.775 litres.

Thus, the rate is;

56.775 litres per 1/60 hour

We want to find in litres/hr.

By proportion, we have it as;

(56.775 ÷ 1/60)/1 = 56.775 × 60 = 3,406.5 litres/hr

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Plz help me, thank you

Kruka [31]

Answer:

$P=40(1.03526)^{t}$

Step-by-step explanation:

<u>Exponential Growth </u>

The natural growth of some magnitudes can be modeled by the equation:

$P=P_o(1+r)^{t}$

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.

The initial number of bacteria is Po=40 and it doubles (P=2Po) at t=20 min. With that point we can find the value of r:

$2P_o=P_o(1+r)^{20}$

Simplifying:

$(1+r)^{20}=2$

Solving for 1+r:

$1+r=\sqrt[20]{2}$

$1+r=1.03526$

The exponential function that models the situation is:

$\mathbf{P=40(1.03526)^{t}}$

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