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2 years ago

Can someone help me here NONSENSE=REPORT

Mathematics

2 answers:

musickatia [10]2 years ago

5 0

Answer:

A circle is named by its center. The center of the given circle is A, therefore:

Name of the circle: A

The radius is any line segment from the center of the circle to the perimeter.

Name 4 radii: $\sf AC, \quad AB, \quad AG, \quad A\,F$

A major arc is an arc whose measure is greater than 180°.

When naming a major arc, the first point and last point are the endpoints, and we also need include the name of any point between those two endpoints.

2 major arcs: $\sf \widehat{CEG},\quad \widehat{BCF}$

A semi-circle is half a circle with an arc that measures 180°.

Its endpoints lie on the diameter of the circle. We need three points to name a semicircle (the endpoints and a point between the endpoints).

A semi-circle: CEF

A minor arc is an arc whose measure is less than 180°.

3 minor arcs: $\sf \widehat{FG}, \quad \widehat{GB}, \quad \widehat{BC}$

A central angle has its vertex at the center of the circle, and is formed by 2 radii. When naming the central angle, the middle letter is the center of the circle.

3 central angles: $\sf \angle F\,AG, \quad \angle GAB, \quad \angle BAC$

The diameter is the widest part of the circle. It is a straight line segment that passes through the center of the circle.

A diameter: CF

Congruent angles are angles with the same measure.
On the diagram, the same angle measures are indicated by the addition of the same number of dashes on the angle sign.

Congruent angles: $\sf \angle F\,AG, \quad \angle GAB$

Adjacent arcs are arcs that have one point in common.

Adjacent arcs: $\sf \widehat{GB}$ and $\sf \widehat{BC}$ (they share point B)

lys-0071 [83]2 years ago

4 0

$\huge \qquad \sf \: Answer$

Here we go ~

1. A circle can be named by their Centre, so here in the diagram it's :

Circle A

2. Name 4 radii :

Radii are the line segments that joins the centre and boundary of circle.

They are :

3. 2 Major arcs :

considering two points on a circle, and joining them forms a curve ( you can say part of circumference )

When we consider two points two arcs are formed and the arc with more length is known as Major Arc

That is :

Major arc ECF
Major arc BEC

4. A Semicircle :

Semicircle is special arc which is formed when two arcs formed by the points are equals to one another... it's also half the Perimeter of circle.

that is :

Arc CF is a Semicircle

5. 3 minor arcs :

The arc formed by two points having lesser length is known as minor arc.

that is :

Arc EF
Arc BG
Arc FG

6. 3 Central angles :

Central angles are angles formed by arcs on centre of the circle ~

that is :

Angle FAB
Angle BAC
Angle GAB

7. A diameter :

Diameter is a chord that passes through centre of the circle.

8. Congruent Angles :

In the given figure, there are two equal/congruent angles that are ~

Angle BAG and Angle GAF

9. Adjacent arcs :

The arcs that have one common end point are known as Adjacent arcs ~

that are :

Arc FG and Arc GB

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Write the exponential function for each table of values. Remember the function y = a(b)*

almond37 [142]

Answer:

Step-by-step explanation:

This is really simple once you get the hang of it. Promise. Remember this:

IF YOU HAVE THE OPPORTUNITY TO CHOOSE A POINT FROM THE TABLE WHERE X = 0, THEN DO IT!

This gives you the a value in your equation and you don't have to solve for it. I'll show you how this looks in the first table of values and then we won't have to do it going forward.

I'm using the coordinates (0, 1) and (1, .5) from the first table. Filling in the equation with the first set of coordinates:

$1=a(b)^0$ and since anything to the 0 power is 1, we know a = 1 (this happens every time we have a coordinate in an exponential table where the x value is 0. a always equals whatever y is!)

Now that we know a = 1, we use that along with the next coordinate pair and solve for b:

$.5=1(b)^1$ which simplifies to

.5 = b and the equation is

$y=1(.5)^x$

For the next table use the coordinate (0, 50) and 1, 25). From the above explanation, I know that a = 50 (because x = 0). Use that along with the next coordinate pair to solve for b:

$25=50(b)^1$ which simplifies to

b = .5 and the equation is

$y=50(.5)^x$

Lastly, use the points (0, 192) and (1, 768) and we know that a = 192; and it follows that

$768=192(b)^1$ so

b = 4 and the equation is

$y=192(4)^x$

The first 2 of these are exponential decay because the number inside the parenthesis is less than 1 but greater than 0; the last one is exponential growth since the number inside the parenthesis is greater than 1. That's how you can tell.

8 0

3 years ago

I need to find the area of the shaded region, can anyone explain how to do it?

vesna_86 [32]

Answer:

Step-by-step explanation:

JM is a diameter. 1/2 JM is the radius. 1/2 10 = 5

The radius is 5

The above statement is true if N is the center.

The semi circle has an area of pi r^2/2 = 5^2/2 * pi = 25/2 * pi

12.5 pi

The area of the other part is

(58/360) * pi * r^2 =

0.161 * pi * 5^2

0.161 * pi * 25

4.03 * pi

Now add these two parts together.

12.5pi + 4.03= 16.53 * pi.

That's one possible answer.

Another would be 16.53 * 3.14 = 51.897

If you have choices, list them.

5 0

3 years ago

What value for x will make the equation true? -3 (7x - 5) = 87 + 3x

Gennadij [26K]

Answer:

x=-3

Step-by-step explanation:

follow the PEMDAS method then see if the 2 equation equal each other after plugging in the x.

7 0

3 years ago

Read 2 more answers

Ten Points For First To Answer Correctly

GalinKa [24]

Answer:

23/34

Step-by-step explanation:

This is guessing you only have fiction books.

6 0

3 years ago

PLSS HELP ASAP TYSM <33 SORRY I COULDN'T FIND SCIENCE LOLL

dimaraw [331]

Answer:

Rock D.

Step-by-step explanation:

We can assume that the force that the catapult does is always the same.

So, here we need to remember Newton's second law:

F = m*a

force equals mass times acceleration.

Where acceleration is the rate of change of the velocity.

So, if we want the rock to hit closer to the catapult, the rock must be less accelerated than rock B.

So, we can rewrite:

a = F/m

So, as larger is the mass of the rock, smaller will be the acceleration of the rock after it leaves the catapult (because the mass is in the denominator). So if we want to have a smaller acceleration, we need to choose a rock with a larger mass than rock B.

Assuming that the mass depends on the size, the only one that has a mass larger than rock B is rock D.

So we can assume that rock D is the correct option.

5 0

3 years ago

Can someone help me here NONSENSE=REPORT​

Can someone help me here NONSENSE=REPORT