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3 years ago

2 tacos cost $6. What is the cost for 6 tacos?

Mathematics

2 answers:

ipn [44]3 years ago

7 0

Answer:

2 tacos = $6

1 tacos = $3

6 tacos = 6 X 3

= $18

18$ is the cost for 6 tacos

erma4kov [3.2K]3 years ago

4 0

Answer:

the answer is 18.

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I am Lyosha [343]

A) 3x (you substitute the g equation into the f one by putting it in the x value for f)

b) x (do the same thing, but switch the letters)

4 0

1 year ago

Express as a difference: a+b, a+5

Tcecarenko [31]

Answer:

a - (-b), a - (-5)

Step-by-step explanation:

A double negative negative is a positive, so a - (-b) = a + b, and a - (-5) is a + 5. However, a double negative is still a difference, so this answer works.

6 0

3 years ago

-11= x-3/2....................................

Alika [10]

Answer:

Hi! The correct answer is x=-19/2

Step-by-step explanation:

~Solve for x by simplifying both sides of the equation, then isolating the variable~

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2 years ago

A shelf has 20 bags of potatoes. Two of the bags have potatoes starting to go bad. The probability of drawing a bag with bad pot

nekit [7.7K]

Probability of drawing bad potatoes = 0.1

The probability of drawing a bag with bad potatoes is less than 1.

The probability of drawing a bag with good potatoes is greater than 0

The probability of drawing a bag with bad potatoes as a decimal .

The probability is 20% which means 20 by hundred , which means there is a chance of being its ok.

probability of bad potatoes = 2/20

=1/10

=0.1

probability of good potatoes = 1- ( probability of bad potatoes)

=1-0.1

=0.9

To learn more about probability

brainly.com/question/173579

#SPJ4

3 0

1 year ago

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

7 0

3 years ago