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Leviafan [203]
3 years ago
11

A triangle has two side lenths of 1 and 16 what is the largest possible whole-number length of the third side?

Mathematics
1 answer:
Afina-wow [57]3 years ago
6 0

Answer:

16

Step-by-step explanation:

Given that:

Length of two sides of the triangle = 1 and 16 ;

The largest possible whole-number length of the third side would be ;

Recall from triangle inequality theorem; the length of any two sides of a triangle is greater than the third side. Therefore. The largest possible whole number value the third side could have is:

Assume the third side is the largest :

Then, the third side must be less than the sum of the other two sides ;

Third side < (16 + 1)

Third side < 17

Therefore, the closest whole number lesser than the sum of the other two sides is (17 - 1) = 16

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Step-by-step explanation:

We are asked to simply (2√5 + 3√2)². Using formula: (a + b)² = a² + b² + 2ab. Let's say 2√5 = a, 3√2 = b. So,

→ (a + b)² = a² + b² + 2ab

→ (2√5 + 3√2)² = (2√5)² + (3√2)² + 2(2√5)(3√2)

We are aware about the fact that root means 1/2 and square of root means 2/2 that is 1. Using this we get:

→ (2√5 + 3√2)² = 4(5) + 9(2) + 2(2√5)(3√2)

Solve the brackets, to do so first put the like terms in one box.

→ (2√5 + 3√2)² = 4(5) + 9(2) + 2(2*3)(√5)(√2)

Solve the rest calculations.

→ (2√5 + 3√2)² = 20 + 18 + 2(6)(√10)

→ (2√5 + 3√2)² = 38 + 12√10

Option (a) (38 + 12√10) is the correct option.

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Answer:

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Step-by-step explanation:

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Think of it this way:

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