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3 years ago

Find the coordinates of the midpoint for line segment JK if J(-9, 5) and K(21.-7)

Mathematics

1 answer:

Trava [24]3 years ago

8 0

Answer:

(6, -1)

Step-by-step explanation:

The coordinates of the midpoint of a line is [(x₁ + x₂)/2, (y₁ + y₂)/2]. For the given line, JK where J = (-9, 5) = (x₁, y₁) and K = (21,-7) = (x₂, y₂).

So [(x₁ + x₂)/2, (y₁ + y₂)/2]

= [(-9 + 21)/2, (5 + (-7))/2]

= [12/2, (5 - 7)/2]

= [12/2, -2/2]

= (6, -1)

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A delivery person uses a service elevator to bring boxes of books up to an office. The delivery person weighs 140 lb and each bo

Stells [14]

Answer:

21 boxes of books

Step-by-step explanation:

guy= 140 lbs

each box= 40lbs elevator can only weigh up to 1010

i took 1010- 140 and got 870lbs left for the books

then i took 870 divided by 40 (to see how many boxes of books can be put on the elevator) and got 21.75

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2 years ago

Use induction to prove that 2? ?? for any integer n>0 . Indicate type of induction used.

Hoochie [10]

Answer with explanation:

The given statement is which we have to prove by the principal of Mathematical Induction

$2^{n}>n$

1.→For, n=1

L H S =2

R H S=1

2>1

L H S> R H S

So,the Statement is true for , n=1.

2.⇒Let the statement is true for, n=k.

$2^{k}>k$

---------------------------------------(1)

3⇒Now, we will prove that the mathematical statement is true for, n=k+1.

$\rightarrow 2^{k+1}>k+1\\\\L H S=\rightarrow 2^{k+1}=2^{k}\times 2\\\\\text{Using 1}\\\\2^{k}>k\\\\\text{Multiplying both sides by 2}\\\\2^{k+1}>2k\\\\As, 2 k=k+k,\text{Which will be always greater than }k+1.\\\\\rightarrow 2 k>k+1\\\\\rightarrow2^{k+1}>k+1$

Hence it is true for, n=k+1.

So,we have proved the statement with the help of mathematical Induction, which is

$2^{k}>k$

3 0

3 years ago

A particle moves along the x-axis with velocity v(t) = t2 - 1, with t measured in seconds and v(t) measured in feet per second.

Kisachek [45]

Answer:

0.667 feet

Step-by-step explanation:

To get the total distance travelled, we would integrate the velocity v(t) equation with respect to time t.

Given that the particle moves from t = 0 to t = 2 seconds

Integrating v(t) = t2 - 1

we get

= t^3/3 - t

substituting the boundaries from t = 0 to t = 2 seconds, we get

= 2^3/3 - 2 - (0^3/3 - 0)

= 8/3 - 2 - 0

= 0.667 feet

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2 years ago

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The graph represents revenue in dollars as a function of greeting cards sold. A coordinate plane showing Greeting Card Revenue,

Travka [436]

Answer:

y=4x

Step-by-step explanation:

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2 years ago

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Which of the following would you round and estimate to a sum of 11?

Leni [432]

Answer:

Step-by-step explanation:

Round and estimate the sum.

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4.89 + 7.431

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The first option is correct.

3 0

3 years ago

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