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bearhunter [10]
3 years ago
8

Find the coordinates of the midpoint for line segment JK if J(-9, 5) and K(21.-7)

Mathematics
1 answer:
Trava [24]3 years ago
8 0

Answer:

(6, -1)

Step-by-step explanation:

The coordinates of the midpoint of a line is [(x₁ + x₂)/2, (y₁ + y₂)/2]. For the given line, JK where J = (-9, 5) = (x₁, y₁) and K = (21,-7) = (x₂, y₂).

So [(x₁ + x₂)/2, (y₁ + y₂)/2]

= [(-9 + 21)/2, (5 + (-7))/2]

= [12/2, (5 - 7)/2]

= [12/2, -2/2]

= (6, -1)

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Stells [14]

Answer:

21 boxes of books

Step-by-step explanation:

guy= 140 lbs

each box= 40lbs                       elevator can only weigh up to 1010

i took 1010- 140 and got 870lbs left for the books

then i took 870 divided by 40 (to see how many boxes of books can be put on the elevator) and got 21.75

so 21 boxes could go on the elevator at a time

5 0
2 years ago
Use induction to prove that 2? ?? for any integer n>0 . Indicate type of induction used.
Hoochie [10]

Answer with explanation:

The given statement is which we have to prove by the principal of Mathematical Induction

    2^{n}>n

1.→For, n=1

L H S =2

R H S=1

2>1

L H S> R H S

So,the Statement is true for , n=1.

2.⇒Let the statement is true for, n=k.

      2^{k}>k

                   ---------------------------------------(1)

3⇒Now, we will prove that the mathematical statement  is true for, n=k+1.

     \rightarrow 2^{k+1}>k+1\\\\L H S=\rightarrow 2^{k+1}=2^{k}\times 2\\\\\text{Using 1}\\\\2^{k}>k\\\\\text{Multiplying both sides by 2}\\\\2^{k+1}>2k\\\\As, 2 k=k+k,\text{Which will be always greater than }k+1.\\\\\rightarrow 2 k>k+1\\\\\rightarrow2^{k+1}>k+1

Hence it is true for, n=k+1.

So,we have proved the statement with the help of mathematical Induction, which is

      2^{k}>k

                 

   

3 0
3 years ago
A particle moves along the x-axis with velocity v(t) = t2 - 1, with t measured in seconds and v(t) measured in feet per second.
Kisachek [45]

Answer:

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Step-by-step explanation:

To get the total distance travelled, we would integrate the velocity v(t) equation with respect to time t.

Given that the particle moves from t = 0 to t = 2 seconds

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we get

= t^3/3 - t

substituting the boundaries from t = 0 to t = 2 seconds, we get

= 2^3/3 - 2 - (0^3/3 - 0)

= 8/3 - 2 - 0

= 0.667 feet

8 0
2 years ago
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Travka [436]

Answer:

y=4x

Step-by-step explanation:

7 0
2 years ago
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Leni [432]

Answer:

A

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The first option is correct.

3 0
3 years ago
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