45+5t=45solving for t
1 answer:
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Answer: The probability that the avg. salary of the 100 players exceeded $1 million is approximately 1.
Explanation:
Step 1: Estimate the standard error. Standard error can be calcualted by dividing the standard deviation by the square root of the sample size:
So, Standard Error is 0.08 million or $80,000.
Step 2: Next, estimate the mean is how many standard errors below the population mean $1 million.
-6.250 means that $1 million is siz standard errors away from the mean. Since, the value is too far from the bell-shaped normal distribution curve that nearly 100% of the values are greater than it.
Therefore, we can say that because 100% values are greater than it, probability that the avg. salary of the 100 players exceeded $1 million is approximately 1.
Answer:
0.025
Step-by-step explanation:
Hello!
Given that the classes are uniformly distributed between 45.0 and 55.0 minutes, the propability distribution will be:
Now, we are looking for a probability P(51.5<x<51.75) which can be computed as:
Therefore:
P(51.5<x<51.75) = 0.025
or
P(51.5<x<51.75) = 2.5%
<em><u>I strongly believe that the answer for both questions have the same answer, I believe this because there is no additional info for a given class or selecting a class. I think both probabilities are the same.</u></em>