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4 years ago

How is finding the factors of a number different from finding the prime factorization of a number.

1 answer:

6 0

When finding factors of a number, you are just finding numbers that can factor into it. When finding the prime factorization, you are narrowing down the factors to the smallest factored numbers.

Ex:   40 •The bolded numbers are the most simplified factors.
/ \
   8 5
/ \
4 2 The prime factorization of 40 is 5 x 2^3.
  / \
2 2

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Write 0.006966 in scientific notation.

mixas84 [53]

Answer:

the answer is 6.966×10^-3

4 0

2 years ago

Choose the solution set represented by the following graph.

Ivan

Answer:

{x | x∈ R, x < -2}

Step-by-step explanation:

Given

See attachment for graph

Required

Determine the inequality

From the attachment, we can see that there is an open circle or -2.

This represents either < or >

Solving further:

The arrow points to the left of -2.

This means that the number line represents numbers less than -2. i.e. < -2

If the numbers are represented with x.

The inequality is: x < -2

So, we have: {x | x∈ R, x < -2}

3 0

3 years ago

the equation is -2x² = 4-3 (x + 1) and the question is justify that it is a 2nd degree equation with the unknown x complete.

Serggg [28]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equation

-2x² = 4-3 (x + 1)

-2x² = 4-3x-3

-2x² = -3x -7

0 = 2x² -3x -7

We know that the degree of the equation is the highest power of x variable in the given equation.

In the equation 0 = 2x² -3x -7 the highest power of x variable in the given equation is 2.

Thus, the degree of the equation is 2.

Also in the equation 0 = 2x² -3x -7, the unknown variable is 'x'.

Let us determine the value 'x'

2x² -3x -7 = 0

Add 7 to both sides

$2x^2-3x-7+7=0+7$

$2x^2-3x=7$

Divide both sides by 2

$\frac{2x^2-3x}{2}=\frac{7}{2}$

$x^2-\frac{3x}{2}=\frac{7}{2}$

Add (-3/4)² to both sides

$x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{7}{2}+\left(-\frac{3}{4}\right)^2$

$x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{65}{16}$

$\left(x-\frac{3}{4}\right)^2=\frac{65}{16}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solving

$x-\frac{3}{4}=\sqrt{\frac{65}{16}}$

$x-\frac{3}{4}=\frac{\sqrt{65}}{\sqrt{16}}$

$x-\frac{3}{4}=\frac{\sqrt{65}}{4}$

Add 3/4 to both sides

$x-\frac{3}{4}+\frac{3}{4}=\frac{\sqrt{65}}{4}+\frac{3}{4}$

$x=\frac{\sqrt{65}+3}{4}$

similarly solving

$x-\frac{3}{4}=-\sqrt{\frac{65}{16}}$

$x=\frac{-\sqrt{65}+3}{4}$

So the solution of the equation will have the values of x such as:

$x=\frac{\sqrt{65}+3}{4},\:x=\frac{-\sqrt{65}+3}{4}$

6 0

3 years ago

3(x+7)=-15 I need a clear explanation of visual representation instead of the answer itself

Arlecino [84]

Answer:

x = -7

Step-by-step explanation:

3(x+7) = -15

First, distributive property. Therefore, you multiply 3 with x and 7

3x + 21 = -15

Then, you need x to be isolated. So you will have to -21 from +21 on both sides of the equation to make it balanced.

3x + 21 = -15

-21 -21 (21 will be canceled from the left side of the equation)

3x = -35

Lastly, you need to divide 3 from both sides of the equation, as 3 is multiplied with x.

3x = -35

3 3 (3 will be canceled from the left side of the equation)

x = -7

4 0

3 years ago

2 b) the urcumference circle=2tr. What is the diametly = 20km? T = 3.14 (3)

zhuklara [117]

comfort room

Step-by-step explanation:

go to the cr and poop outside eta eta

3 0

3 years ago