<img src="https://tex.z-dn.net/?f=2x%20%2B%204y%20%3D%204" id="TexFormula1" title="2x + 4y = 4" alt="2x + 4y = 4" align="absmidd

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MAVERICK [17]

3 years ago

le" class="latex-formula">
solve

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

7 0

$\bf 2x+4y=4\implies 4y=4-2x\implies y=\cfrac{4-2x}{4}\implies y=\cfrac{4}{4}-\cfrac{2x}{4}
\\\\\\
y=1-\cfrac{x}{2}$

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Ed is on a road trip. He has already traveled 211 miles and is driving at a rate of 63 miles per hour. Which equation could be u

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Answer:

Option C is correct.

Step-by-step explanation:

Distance already traveled by Ed $=211$ miles

Also, Ed is driving at a rate of 63 miles per hour.

Distance $=$ Speed × Time

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Also, total distance traveled by Ed is $638$ miles.

Therefore,

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In college basketball, a shot made from beyond a designated arc radiating about 20 ft from the basket is worth three points ins

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Answer:

a) By the Central Limit Theorem, the distribution would be approximately normal, with mean $\mu = 0.45$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497$

b) 4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered surprising, so yes, it would be surprising for him to make only 25 of these shots.

Step-by-step explanation:

To solve this question, we are going to need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

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Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For proportions, we have that the mean is $\mu = p$ and the standard deviation is $s = \sqrt{\frac{p(1-p)}{n}}$

In this problem, we have that:

$p = 0.45, n = 100$

a)By the Central Limit Theorem, the distribution would be approximately normal, with mean $\mu = 0.45$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497$

b)This is Z when X = 0.25.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.25 – 0.45}{0.0497}$

$Z = -4.02$

4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered

surprising, so yes, it would be surprising for him to make only 25 of these shots.

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2 years ago