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natulia [17]
3 years ago
14

A small moving box has a volume of 2304 inches cubed and length of 16 inches. The box's width and height are the same. Write the

equation that models the volume of the box. Let x represent the width. Solve the equation. Find the width and height of the box.
Mathematics
1 answer:
lisabon 2012 [21]3 years ago
8 0

Answer:

<em>V = 16x² </em>

<em>Width = 12in</em>

<em>Height = 12in</em>

Step-by-step explanation:

Volume of the box is expressed as;

V = Length *Width * height

Given

Length = 16in

Width = x

Height = x

The volume of the box will be expressed as;

V = 16 * x * x

<em>V = 16x² (This gives the required equation)</em>

To get x:

We are given

V = 2304in³

Substitute;

2304 = 16x²

x² = 2304/16

x² = 144

x= √144

x = 12

<em>Hence the width and the height are both 12inches since they are the same.</em>

<em></em>

For the sma

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Answer:

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Step-by-step explanation:

The equation for the volume of a cone is:

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V = 414.48

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Plug in those values and solve for h:

414.48 = 1/3(3.14)(6)^2h

414.48 = 37.68h ; divide both sides by 37.68

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6 0
3 years ago
Please help me please!<br> Also, please show your work image shown below in attachment
WINSTONCH [101]

Answer:

see below

Step-by-step explanation:

some of your answers that you currently have are wrong, I'll note those mistakes below

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5x+15 = 5(x+3), not (x+3)(x+5)

ie  \frac{10x^2+20x}{x+2}

we see that 10x can divide the numerator in a whole number ratio

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second mistake: the first binomial expansion is incorrect.

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The equation is
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ycow [4]

Answer:

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6 0
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