The measure of Arc Q P is 96°. We also know that ∠QTP is central angle, then the measure of arc QP is 96°.
Step-by-step explanation:
<u>Step 1</u>
If QS is a circle diameter,
then m∠QTS=180°.
Let x be the measure of angle RTQ: ∠RTQ =x.
so, let ∠RTQ = x
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<u>Step 2</u>
According to the question,
∠RTQ = ∠RTS - 12°
⇒ ∠RTS = x + 12°
∴ ∠QTS = ∠RTQ + ∠RTS
= x + x + 12° = 2x + 12° = 180°
⇒ 2x = 168°
⇒ x = 84°
⇒ ∠RTQ = 84°
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<u>Step 3</u>
Now,
∵∠QTP and ∠RTS are vertical angles
∴ ∠QTP = 84° + 12° = 96°
As ∠QTP is the central angle, hence the measure of arc QP is 96°
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<u>Step 4</u>
The Measure of arc QP = 96°
Answer:
True,True,3=8-5 (y=3),E,39
Step-by-step explanation:
Answer:
3x(2x - 3)(2x + 3)(5x - 1).
Step-by-step explanation:
60x4 − 12x3 − 135x2 + 27x
= 3x(20x^3 - 4x^2 - 45x + 9) We can factor what's in the parentheses by grouping:
= 3x(4x^2( 5x - 1) - 9(5x - 1))
= 3x (4x^2 - 9)(5x - 1) Now we factors 4x^2 - 9:
= 3x(2x - 3)(2x + 3)(5x - 1).