Jim wants to build a toy house. He plans for the width to be 2 feet and the length to be 3 feet. Then he decides to add to the l
ength. The amount he wants to add to the length is shown by the variable y .
1 answer:
Lets w width, l length, y amount add, A area, P perimeter
A=lw=(3+y)(2)=6+2y ft²
p= 2l+2w= 2(3+y)+2(2)= 6+2y+4 =10+2y
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▪ Answer:
n = 17
d = 8
▪ Step-by-step explanation:
Hi there !
1 nickel = 5c
1 dime = 10c
$1.65 = 165c
n + d = 25 => n = 25 - d
5n + 10d = 165
replace n
5(25 - d) + 10d = 165
125 - 5d + 10d = 165
5d = 165 - 125
5d = 40
d = 8 (dimes)
n = 25 - d
n = 25 - 8
n = 17 (nickels)
Good luck !
Answer:
9.0586 OR
9.06
Step-by-step explanation:
IDK, used fusion 360
The LCM of 6 and 15 is 30:)
.008 is the answer you are looking for :)
![\sqrt{55 } = 7.41.....](https://tex.z-dn.net/?f=%20%5Csqrt%7B55%20%7D%20%20%3D%207.41.....)
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