Answer:
![\sec \theta = \frac{\sqrt{22}}{4}](https://tex.z-dn.net/?f=%5Csec%20%5Ctheta%20%3D%20%5Cfrac%7B%5Csqrt%7B22%7D%7D%7B4%7D)
Step-by-step explanation:
Given
![\tan^2 \theta = \frac{3}{8}](https://tex.z-dn.net/?f=%5Ctan%5E2%20%5Ctheta%20%3D%20%5Cfrac%7B3%7D%7B8%7D)
Required
![\sec\ \theta](https://tex.z-dn.net/?f=%5Csec%5C%20%5Ctheta)
We have:
![\sec^2\theta = 1 + \tan^2 \theta](https://tex.z-dn.net/?f=%5Csec%5E2%5Ctheta%20%3D%201%20%2B%20%5Ctan%5E2%20%5Ctheta)
This gives:
![\sec^2\theta = 1 + \frac{3}{8}](https://tex.z-dn.net/?f=%5Csec%5E2%5Ctheta%20%3D%201%20%2B%20%5Cfrac%7B3%7D%7B8%7D)
Take lcm and solve
![\sec^2\theta = \frac{9+3}{8}](https://tex.z-dn.net/?f=%5Csec%5E2%5Ctheta%20%3D%20%5Cfrac%7B9%2B3%7D%7B8%7D)
![\sec^2\theta = \frac{11}{8}](https://tex.z-dn.net/?f=%5Csec%5E2%5Ctheta%20%3D%20%5Cfrac%7B11%7D%7B8%7D)
Take square roots
![\sec \theta = \frac{\sqrt{11}}{\sqrt 8}](https://tex.z-dn.net/?f=%5Csec%20%5Ctheta%20%3D%20%5Cfrac%7B%5Csqrt%7B11%7D%7D%7B%5Csqrt%208%7D)
![\sec \theta = \frac{\sqrt{11}}{2\sqrt 2}](https://tex.z-dn.net/?f=%5Csec%20%5Ctheta%20%3D%20%5Cfrac%7B%5Csqrt%7B11%7D%7D%7B2%5Csqrt%202%7D)
Rationalize
![\sec \theta = \frac{\sqrt{11}}{2\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}](https://tex.z-dn.net/?f=%5Csec%20%5Ctheta%20%3D%20%5Cfrac%7B%5Csqrt%7B11%7D%7D%7B2%5Csqrt%202%7D%20%2A%20%5Cfrac%7B%5Csqrt%202%7D%7B%5Csqrt%202%7D)
![\sec \theta = \frac{\sqrt{22}}{4}](https://tex.z-dn.net/?f=%5Csec%20%5Ctheta%20%3D%20%5Cfrac%7B%5Csqrt%7B22%7D%7D%7B4%7D)
Answer:
1.32lb
Step-by-step explanation:
We will first have to calculate the grams to kilogram,
600g = 0.6kg
Since 1 kilogram represents 2.2 pound we will multiply 0.6 by 2.2 to get the pounds
0.6 * 2.2
= 1.32lb
The number for x after the equals should be a 4
6 + 7i = 6 - 7i
Hope this helped!