Compose the quadratic condition in standard shape, ax2 + bx + c = 0. Recognize the values of a, b, c. Write the Quadratic Equation. At that point substitute within the values of a, b, c. Simplify. Check the arrangements.
Answer:
37.7
Step-by-step explanation:
The orginal answer is 37.699
But you want to round the tenth
So 9 to the 6 you want to rasie the score
6 turns into a 7 and the numbers behind it (9 and the other 9) turn into a zero
37.7 or 37.700
Answer:
87.92
Step-by-step explanation:
3.14(a²+ab)=
<em>Plugging in values for a and b</em>
3.14(4²+4×3)=
3.14(16+12)=
3.14(28)=
87.92
Answer:
b.
Step-by-step explanation:
We have to look at sign changes in f(x) to determine the possible positive real roots.
There is only one sign change here, between the -8x and the +4. So that means there is only 1 possible real positive root.
Now we have to look at sign changes in f(-x) to determine the possible negative real roots.
There are 3 sign changes here. That means there are either 3 negative roots or 3-2 = 1 negative root. So we have:
1 positive
3 or 1 negative
We need to pair them up now with all the possible combinations.
If we have 1 positive and 1 negative, we have to have 2 imaginary
If we have 1 positive and 3 negative, we have to have 0 imaginary
Keep in mind that the total number or roots--positive, negative, imaginary--have to add up to equal the degree of the polynomial. This is a 4th degree polynomial, so we will have 4 roots.