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muminat
2 years ago
7

the following 3 shapes are made up of square, circles, and semi circles. Find the Area and perimeter of the shaded area. Write y

our answer as a completely simplified exact value in terms of pi

Mathematics
1 answer:
koban [17]2 years ago
5 0

Answer:

Perimeter = 18 + 9pi

Area = 81 - 20.25*pi

Step-by-step explanation:

Perimeter = 9 + 9 + 2(2 pi r)/2     The twos cancel out.

Perimeter = 18 + 9*pi

Area of the square = 9 * 9 = 81 cm^2

Area of the 2 semicircles = 2 * pi * r^2/2

r = d/2

d = 9

r = 9/2 = 4.5

Area of the 2 semicircles = 2 (pi * 4.5^2)/2

Area of the 2 semicircles = 20.25 pi

Area of the blue figure = 81 - 20.25 pi

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Answer:

1136 received each day

Step-by-step explanation:

148(2)+4=   1136

8 0
2 years ago
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along
mina [271]

Answer:

The tip of the man shadow moves at the rate of \frac{20}{3} ft.sec

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

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Cross multiplying, we get

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We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt} ----(1)

We are given \frac{dx}{dt} = 4 ft/sec. Plug in the equation (1), we get

\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

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3 years ago
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