4 years ago

Can someone help me solve this question? It’s similar to the previous ones! Thank you!

Mathematics

1 answer:

luda_lava [24]4 years ago

8 0

Answer:

$\boxed{\sf \ \ \ (-2x+-9)(1x+3)=-2x^2-15x-27 \ \ \ }$

the coefficient c is -27

Step-by-step explanation:

hello

$(-2x+-9)(1x+3)=(-2x-9)(x+3)=-2x(x+3)-9(x+3)=-2x^2-6x-9x-27\\=-2x^2-15x-27$

hope this helps

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Find an for the arithmetic series with s16 = -288 And a1 =-21

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If $d$ is the common difference between terms in the sequence $\{a_n\}$ , then

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...
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You're told that $S_{16}=-288$ (the sum of the first 16 terms in the sequence, presumably). Well, we know that

$S_{16}=\displaystyle\sum_{n=1}^{16}a_n=\sum_{n=1}^{16}(-21+(n-1)d)$
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3 years ago

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Answer:

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3 years ago

The equation of the line through (3 -4) with slope 2/3 is:<br> WILL GIVE BRAINLIST

LUCKY_DIMON [66]

Answer:

$y = \frac{2}{3}x - 6$ .

Step-by-step explanation:

(3 , -4) ; slope(m) = 2/3

y - y1 = m (x -x1)

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