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mamaluj [8]
3 years ago
13

Sabiendo que 16x10=160¿como resolverías, sin hacer la cuenta escrita los siguientes calculos?A_16x20=

Mathematics
1 answer:
-Dominant- [34]3 years ago
7 0

Answer:

A_16x20=320

Step-by-step explanation:

Esto se puede hacer fácilmente de 2 formas.

1) 20 se puede dividir en un múltiplo de 10 y luego multiplicar

16 x 20 =16 x 10 x 2 = 160 x 2 = 320

2) Uso de cero.

Cualquier cosa multiplicada por cero da un cero y luego multiplicar el otro número da el resultado.

16 x 20 = (16 x 2) * 10 = (32) 10 = 320

Así que separamos el cero añadiéndole un 1, lo que lo convierte en 10 y obtenemos el mismo resultado.

This can be easily done in 2 ways .

1) 20 can be broken into a multiple of 10 and then multiplied

16 x 20 =16 x10 x 2=160x 2= 320

2) Use of zero.

Anything multiplied with zero gives a zero and then multiplying the other number gives the result.

16 x 20 = (16x 2) *10= (32)10= 320

So we separated the zero by adding a 1 to it thus making it 10 and we get the same result.

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Answer:

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Answer:

The answer is below

Step-by-step explanation:

The horizontal asymptote of a function f(x) is gotten by finding the limit as x ⇒ ∞ or x ⇒ -∞. If the limit gives you a finite value, then your asymptote is at that point.

\lim_{x \to \infty} f(x)=A\\\\or\\\\ \lim_{x \to -\infty} f(x)=A\\\\where\ A\ is\ a\ finite\ value.\\\\Given\ that \ f(x) =25000(1+0.025)^x\\\\ \lim_{x \to \infty} f(x)= \lim_{x \to \infty} [25000(1+0.025)^x]= \lim_{x \to \infty} [25000(1.025)^x]\\=25000 \lim_{x \to \infty} [(1.025)^x]=25000(\infty)=\infty\\\\ \lim_{x \to -\infty} f(x)= \lim_{x \to -\infty} [25000(1+0.025)^x]= \lim_{x \to -\infty} [25000(1.025)^x]\\=25000 \lim_{x \to -\infty} [(1.025)^x]=25000(0)=0\\\\

Since\  \lim_{x \to -\infty} f(x)=0\ is\ a\ finite\ value,hence:\\\\Hence\ the\ horizontal\ asymtotes\ is\ at\ y=0

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