The given statement is:
An integer is divisible by 100 if and only if its last two digits are zeros
The two conditional statements that can be made are:
1) If an integer is divisible by 100 its last two digits are zeros.
This is a true statement. If a number is divisible by 100, it means 100 must be a factor of that number. When 100 will be multiplied by the remaining factors, the number will have last two digits zeros.
2) If the last two digits of an integer are zeros, it is divisible by 100.
This is also true. If last two digits are zeros, this means 100 is a factor of the integer. So the number will be divisible by 100.
Therefore, the two conditional statements that are formed are both true.
So, the option A is the correct answer.
Yes, it is. When the definition is separated into two conditional statements, both of the statements are true
Answer:
B) 8 and 24.
Step-by-step explanation:
Just by looking at the answer choices, since one number must be three times the other, we can determine that the correct answer is B.
Regardless, let's work this out mathematically. Let the first number be <em>a</em> and the second number be <em>b</em>.
Their difference is 16. Hence:
The first number is three times the second number. So:
Substitute:
Solve for <em>b</em>. Subtract:
And divide both sides by two:
So, the second number is 8.
And since the first number is three times the second, the first number is 24.
Our answer is B as expected.
His mistake is he didn't make 6/10 to 60/100 he added them without changing the 6/10
