Answer:
Dimensions to minimize surface are is 28 ft x 28 ft x 14 ft
Step-by-step explanation:
The Volume of a box with a square base of say;x cm by x cm and height
h cm is;
V = x²h
Now, the amount of material used is directly proportional to the surface area, hence we will minimize the amount of material by minimizing the surface area.
The formula for the surface area of the box described is given by;
A = x² + 4xh
However, we need A as a function of
only x, so we'll use the formula;
V = x²h
V = x²h = 10,976 ft³
So,
h = 10976/x²
So,
A = x² + 4x(10976/x²)
A = x² + 43904/x
So, to minimize the area, it will be at dA/dx = 0.
So,
dA/dx = 2x - 43904/x² = 0
Factorizing out, we have;
2x³ = 43904
x³ = 43904/2
x³ = 21952
x = ∛21952
x = 28 ft
since, h = 10976/x²
h = 10976/28² = 14 ft
Thus,dimension to minimize surface are is 28 ft x 28 ft x 14 ft
Slope = 1-5/0-1 = 4
the answer is 4
Short answer 3 times as much = 54 m^3 <<<<< answer
The volumes are krelated by k So solve for k
Volume of Cylinder = k Volume of the cone.
pi r^2 h = k(1/3 pi r^2 h) Since you know that r is the same in both and so is h they divide out.
divide by h
pi r^2 = k (1/3 pi r^2 Divide by pi
r^2 = k (1/3 r^2 ) Divide by r^2
1 = k (1/3) multiply by 3
3 = k
The volume will be 3 times as much.as the cone.
3 * 18 = volume of cylinder.
54 <<<< volume of cylinder.
Answer:
C
Step-by-step explanation:
using
x × y = 
, then
2 × 4
= 
= 
= 
= 6
Answer:
1
Step-by-step explanation:
