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gogolik [260]
2 years ago
10

Negative 2 (x + 5) = negative 2 (x minus 2) + 5 What is the solution to Yuto's equation? –10 9 no solution infinitely many solut

ions
Mathematics
1 answer:
sweet [91]2 years ago
6 0
576gffgghuttgh
Vgfgvcv
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Round 1289.48 to the nearest dollar please
Ilya [14]
$1290 or you could use 1289.50
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3 years ago
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When making a long distance call from a certain pay phone, the first three minutes of a call cost $2.10. After that, each additi
Sauron [17]

Answer: the number of minutes of long distance call that one can make is lesser than or equal to 12 minutes.

Step-by-step explanation:

Let x represent the number of minutes of long distance call that one makes.

The first three minutes of a call cost $2.10. After that, each additional minute or portion of a minute of that call cost $0.45. This means that if x minutes of long distance call is made, the total cost would be

2.10 + 0.45(x - 3)

Therefore, the inequality to find the number of minutes one can call long distance for $6.15 is expressed as

2.10 + 0.45(x - 3) ≤ 6.15

2.10 + 0.45x - 1.35 ≤ 6.15

0.75 + 0.45x ≤ 6.15

0.45x ≤ 6.15 - 0.75

0.45x ≤ 5.4

x ≤ 5.4/0.45

x ≤ 12

4 0
4 years ago
What percent of 82.5 is 21.12
Travka [436]
<span>21.12 is 25.6% of 82.5</span>

hope this helps!! :)
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8 0
3 years ago
Read 2 more answers
Can someone please answer this
kaheart [24]

Answer:

<h2>{7}^{3} (as \: a \: single \: power \: of \: 7)</h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u> </u></em><em><u> </u></em>

{7}^{4}  \div 7

<em><u>Since</u></em><em><u>,</u></em>

{a}^{x}  \div  {a}^{y}  =  {a}^{x - y}

<em><u>Hence</u></em><em><u>,</u></em>

=  {7}^{4 - 3}

=  {7}^{3} (ans)(as \: a \: single \: power \: of \: 7)

8 0
3 years ago
Noah says to find 20% of a number he divides the number by 5. Is this true explain your answer
Nutka1998 [239]

Answer:

yes

Step-by-step explanation:

note that 20% = \frac{20}{100} = \frac{1}{5}

Hence to find 20% of a number, dividing the number by 5 is correct

20% of £30 = \frac{30}{5} = £6


5 0
3 years ago
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