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Tatiana [17]
3 years ago
10

Please help me with this problem

Mathematics
1 answer:
choli [55]3 years ago
3 0
You multiply all the numbers together
You might be interested in
A cup of cereal has 12 grams of fiber, which is 40% of the recommended daily amount.
Papessa [141]

The recommended daily amount of fiber is 30 grams.

Step-by-step explanation:

Quantity of fiber in one cup = 12 grams

It is 40% of our daily recommended amount.

Let,

x be the quantity of fiber recommended daily.

40% of x = 12

\frac{40}{100}*x=12\\

0.4x=12

Dividing both sides by 0.4

\frac{0.4x}{0.4}=\frac{12}{0.4}\\x=30

The recommended daily amount of fiber is 30 grams.

Keywords: percentage, division

Learn more about percentages at:

  • brainly.com/question/730852
  • brainly.com/question/7419893

#LearnwithBrainly

4 0
3 years ago
What is (-100)a×56 and thanks​
Stella [2.4K]
Hey there!
First, we will multiply -100 by a.
-100 x a = -100a
Now we have:
-100a x 56
Let’s multiple this as well.
-100a x 56 = -5600a
Your answer is -5600a.
Hope this helps!
4 0
3 years ago
Plsss answer need help fasttttttttttt
alexgriva [62]
10 1/2 or 10.5

Step by step explanation

8+1/2+2+4
Add the whole fractional parts Separately

(8-2+4)+1/2
calculate

10+1/2
Write as a mixed number
7 0
3 years ago
Find the volume of the solid bounded by z = 2 - x2 - y2 and z = 1. Express your answer as a decimal rounded to the hundredths pl
butalik [34]

Answer:

The answer is "(\frac{\pi}{2})".

Step-by-step explanation:

z = 2 - x^2 - y^2.........(1) \\\\z = 1.............(2)  

Let add equation 1 and 2:

Using formula: x^2+y^2=1 \\\\

convert to polar coordinates

r=2

\theta \varepsilon (0=\pi)=z\\\\V=\int^{2\pi}_{\theta=0}\int^{1}_{\pi=0}\int^{z_{2}}_{z_1} r \ dr \d \theta\\\\

    =\int^{2\pi}_{0}\int^{1}_{0}  (Z_2-z_1)r  \ dr \d \theta\\\\=\int^{2\pi}_{0}\int^{1}_{0} 1- (-1-x^2-y^2) r \ dr \d \theta\\\\=\int^{2\pi}_{0}\int^{1}_{0} (+1 \pm r^2) r \ dr \d \theta\\\\=\int^{2\pi}_{0}\int^{1}_{0} (-r^3 + r)  \ dr \d \theta\\\\=\int^{2\pi}_{0} (-\frac{r^4}{4}+\frac{r^2}{1})^{1}_{0}  \d \theta\\\\=\int^{2\pi}_{0} (\frac{1}{4})  \d \theta\\\\=(\frac{2 \pi}{4}) \\\\=(\frac{\pi}{2}) \\\\

8 0
3 years ago
Need Help!...anyone!
faust18 [17]

(a)

\sqrt[5]{ {x}^{3} }

(b)

\sqrt[8]{x}

(c)

\sqrt[3]{ {x}^{5} }

(d)

\sqrt{ {x}^{3} }

4 0
3 years ago
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