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choli [55]
3 years ago
15

What is the solution to the system of liner equations shown on the graph?

Mathematics
1 answer:
Valentin [98]3 years ago
5 0

Answer:

C The system has no solution

Step-by-step explanation:

They are parallel lines so there is no solution :).

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Angles A M Y and Y M B form a line. Angles Y M B and B M X form a line. Angles X M A and A M Y form a line. Choose each angle to
ExtremeBDS [4]

Answer:

AMY

BMY

BMX

Step-by-step explanation:

I took the assignment

3 0
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What multiples for 90 and adds up to -23 ?
melamori03 [73]

Easy buddy...

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Step (1)

I choose a number which is x

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90x

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Adds up to -23 :

90x - 23

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Thanks for watching buddy good luck.

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7 0
3 years ago
Which inverse operation would be used to verify the following equation? 54 ÷ 9 = 6        A. 9 − 6 = 3   B. 54 ÷ 6 = 9   C. 9 ×
Gnom [1K]
9 X 6 = 54. They are opposite operations
4 0
2 years ago
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What is the exact volume of a cylinder that has a height of 1.8 ft and a radius of 6.1 ft?
lozanna [386]
Cylinder area=height times area of base (area of base=area of circle)

height =1.8
radius=6.1
area of circle=pi times r^2


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3 0
3 years ago
Use the discriminant to determine the number of solutions to the quadratic equation 3x^2+5x=-1
kari74 [83]

Answer:

Two real distinct solutions

Step-by-step explanation:

Hi there!

<u>Background of the Discriminant</u>

The discriminant b^2-4ac applies to quadratic equations when they are organised in standard form: ax^2+bx+c=0.

All quadratic equations can be solved with the quadratic formula: x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}.

When b^2-4ac is positive, it is possible to take its square root and end up with two real, distinct values of x.

When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.

When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.

<u>Solving the Problem</u>

<u />3x^2+5x=-1<u />

We're given the above equation. It hasn't been organised completely in ax^2+bx+c=0, but we can change that by adding 1 to both sides to make the right side equal to 0:

3x^2+5x+1=0<u />

Now that we can identify the values of a, b and c, we can plug them into the discriminant:

D=b^2-4ac\\D=(5)^2-4(3)(1)\\D=25-4(3)(1)\\D=25-12\\D=13

Therefore, because the discriminant is positive, the equation has two real, distinct solutions.

I hope this helps!

4 0
3 years ago
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