Answer:
Step-by-step explanation:
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Transla
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Quiz 1
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Unit
Do 5 problems
Answer:
0.3891 = 38.91% probability that only one is a second
Step-by-step explanation:
For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
17% of its goblets have cosmetic flaws and must be classified as "seconds."
This means that 
Among seven randomly selected goblets, how likely is it that only one is a second
This is P(X = 1) when n = 7. So


0.3891 = 38.91% probability that only one is a second
Its 249 because the difference 726-447 is 249
Answer:
120
Step-by-step explanation:
15 x 16/2
You double 8 because your rotating around the y-axis
Answer: B) y=6/11.
To find the horizontal asymptote(s) you must find the limit as x approaches infinity and the limit as x approaches -infinity.
Using L’Hôpital’s rule:
lim x-> infinity (f(x))=6/11.
lim x-> -infinity (f(x))=6/11.