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kiruha [24]
3 years ago
8

2−6(−5t+1) im stuck please help. Also you can't simplify it all the way

Mathematics
2 answers:
BigorU [14]3 years ago
7 0
Your answer would be 30t - 4
Alenkasestr [34]3 years ago
7 0
The answer is -4 + 30t
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Is (0,0) a solution to 6x - 7y > 20 please include the steps!
leonid [27]

Answer:

No.

Step-by-step explanation:

To determine if (0,0) is a solution to the inequality, substitute 0 for x and 0 for y and check to see. Thus:

6x-7y>20

Substitute 0 for x and 0 for y:

6(0)-7(0)\stackrel{?}{>}20

Multiply:

0-0\stackrel{?}{>}20

Subtract:

0\not>20

So, (0,0) is <em>not</em> a solution.

And we're done!

8 0
3 years ago
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Marisha walks 8 miles in 5 days. If she walks at the same rate, how far
stiv31 [10]

Answer:

56 miles

Step-by-step explanation:

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3 years ago
Please help 10 Points​
QveST [7]

Answer:

c

Step-by-step explanation:

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3 years ago
Based on a study of population projections for 2000 to​ 2050, the projected population of a group of people​ (in millions) can b
Olegator [25]

Answer:

(a) 0.107 million per year

(b) 0.114 million per year

Step-by-step explanation:

A(t) = 11.19(1.009)^t

(a) The average rate of change between 2000 and 2014 is determined by dividing the difference in the populations in the two years by the number of years. In the year 2000, t=0 and in 2014, t=14. Mathematically,

\text{Rate}=\dfrac{A(2014) - A(2000)}{2014-2000}=\dfrac{11.19(1.009)^14-11.19(1.009)^0} {14}

A(0)=\dfrac{12.69-11.19}{14}=\dfrac{1.5}{14}=0.107

(b) The instantaneous rate of change is determined by finding the differential derivative at that year.

The result of differentiating functions of the firm y=a^x (where a is a constant) is \dfrac{dy}{dx}=a^x\ln a. Let's use in this in finding the derivative of A(t).

A\prime(t) = \dfrac{A}{t}=11.19\cdot1.009^t\ln1.009

In the year 2014, t=14.

A\prime(14) =11.19\cdot1.009^14\ln1.009=0.114

6 0
3 years ago
Write a sentence representing the equation x+56/7=11
Anastasy [175]
Hey there! :D

x+56/7=11

A number plus fifty-six sevenths is equal to eleven. 

I hope this helps!
~kaikers
8 0
4 years ago
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