Answer:
Step-by-step explanation:
Given,
The sum of three integers is 92
So,
Let,
The first integer be "x"
The second integer be "y"
The third integer be "z"
Now,
According to the question,
y = 3x ..............equation (1)
z = 2x - 10 .............. equation (2)
x + y + z = 92 ..............equation (3)
Now,
Substituting the value of "y" and "z" from equation (1) and (2), we get,
x + (3x) + (2x - 10) = 92
x + 3x + 2x - 10 = 92
6x - 10 = 92
6x = 92 + 10
x = 102 / 6
x = 17
Now,
substituting the value of "x" in equation (1)
y = 3 (17)
y = 51
Now,
Substituting the value of "x" in equation (2),
z = 2 (17 ) - 10
z = 34 - 10
z = 24
So, the numbers are 17, 51 and 24
NEVER HATE MATH!!!
Answer:
(0,-5). y=mx+b or -5=0 × 0+b, or solving for b: b=-5-(0)(0). b=-5.
(2,-5). y=mx+b or -5=0 × 2+b, or solving for b: b=-5-(0)(2). b=-5.
y=-5
Answer:
x=5
Step-by-step explanation:
9x^2 - 2x + 25 = 8x^2 + 8x
9x^2-8x^2-2x-8x+25=0
x^2-6x+25=0 factorize
(x-5)(x-5)=0
x-5=0 then x=5
Answer:
The first one is ur answer
Step-by-step explanation:
