The sum of three integers is 92. The second number is three times the first number. The third number is ten less than twice the first number. Find the integers. I hate math.
1 answer:
Given, The sum of three integers is 92 So, Let, The first integer be "x" The second integer be "y" The third integer be "z" Now, According to the question, y = 3x ..............equation (1) z = 2x - 10 .............. equation (2) x + y + z = 92 ..............equation (3) Now, Substituting the value of "y" and "z" from equation (1) and (2), we get, x + (3x) + (2x - 10) = 92 x + 3x + 2x - 10 = 92 6x - 10 = 92 6x = 92 + 10 x = 102 / 6 x = 17 Now, substituting the value of "x" in equation (1) y = 3 (17) y = 51 Now, Substituting the value of "x" in equation (2), z = 2 (17 ) - 10 z = 34 - 10 z = 24So, the numbers are 17, 51 and 24 NEVER HATE MATH!!!
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