Using the intersecting chord theorem:
15 x 2 = 5 x n
Simplify:
30 = 5n
Divide both sides by 5:
n = 30/5
n = 6 m
8 x n+8 = 16 x n+2
Simplify:
8n +64 = 16n +32
Subtract 8n from both sides:
64 = 8n +32
Subtract 32 from both sides:
32 = 8n
Divide both sides by 8:
n = 32 /8
n = 4
Answer:
64
Step-by-step explanation:
Find the area of both triangles inside the bigger triangle and add them together.
Use the Pythagorean theorem to find the missing length of the leg in the smallest triangle:
a² + b² = c²
8² + b² = 10²
64 + b² = 100
36 = b²
6 = b
Calculate the area of the smaller triangle:
1/2(<em>b</em>x<em>h</em>)
1/2(6 x 8)
1/2(48)
24
Calculate the area of the bigger triangle:
<em>We know that the longer leg is 10 units because we were able to subtract the length of the smaller triangle's leg from 16.</em>
1/2(<em>b</em>x<em>h</em>)
1/2(10 x 8)
1/2(80)
40
Add both areas to find the area of the largest triangle:
40 + 24 = 64
Answer:
77.25 cm^2
Step-by-step explanation:
Area of a regular octagon :
2a^2(1 + (sqrt2))
where a is the side
substitute 4 in for 'a'
Answer:
A. 2/3
Opposite Sides of a Parallelogram
The two pairs of sides in a parallelogram are parallel to each other.
Parallel lines have the same slope.
The slope of the opposite sides of a parallelogram are congruent (equal in measure).
Given:
Slope of PQ = 2/3
Slope of QR = -1/2
For PQRS to be a parallelogram, the slope of SR must be same as the slope of PQ.
This implies that: Slope of SR = Slope of PQ = 2/3.
Therefore, based on the properties of a parallelogram, the slope of SR for PQRS to be a parallelogram would be: 2/3.
20 and 10, 20 is 2 times 10 and if you add them together its 30
