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Gelneren [198K]
3 years ago
5

The sum of three integers is 92. The second number is three times the first number. The third number is ten less than twice the

first number. Find the integers. I hate math.
Mathematics
1 answer:
SVEN [57.7K]3 years ago
3 0
Given,
The sum of three integers is 92

So,
Let,
The first integer be "x"
The second integer be "y"
The third integer be "z"

Now,
According to the question,
y = 3x          ..............equation (1)
z = 2x - 10    .............. equation (2)
x + y + z = 92 ..............equation (3)

Now,
Substituting the value of "y" and "z" from equation (1) and (2), we get,

x + (3x) + (2x - 10) = 92
    x + 3x + 2x - 10 = 92
                  6x - 10 = 92
                         6x = 92 + 10
                           x = 102 / 6
                           x = 17

Now,
substituting the value of "x" in equation (1)
 y = 3 (17)
y = 51

Now,
Substituting the value of "x" in equation (2),

z = 2 (17 ) - 10
z = 34 - 10
z = 24


So, the numbers are 17, 51 and 24


NEVER HATE MATH!!!
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