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lilavasa [31]
3 years ago
6

How many moles of Al2O3 will be produced if 1.35 moles of Fe are produced?

Chemistry
1 answer:
Sergeu [11.5K]3 years ago
5 0

Answer:

0.675 mol

Explanation:

Step 1: Write the balanced equation

2 Al + Fe₂O₃ ⇒ 2 Fe + Al₂O₃

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of Fe to Al₂O₃ is 2:1.

Step 3: Calculate the moles of Al₂O₃ produced when 1.35 moles of Fe are produced

We will use the established molar ratio.

1.35 mol Fe × 1 mol Al₂O₃/2 mol Fe = 0.675 mol Al₂O₃

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Explanation:

The atoms of one element differs from the atoms of other elements in terms of the number of protons they contain. This is often taken as the atomic number of such an atom.

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Neutralizing an olympic size swimming pool is conceptually very similar to performaing a massive titration experiment. Suppose a
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Answer:

6,97x10⁻³ gallons

Explanation:

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pH = -log [H⁺]

Thus, you need to have, in the end:

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And you have, in the first:

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The volume of swimming pool is:

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Thus, the moles of H⁺ in the first and in the end are:

First:

10^{-9,33}mol/L × 2649787L = 1,24x10⁻³ moles

End:

10^{-7}mol/L × 2649787L = 0,265 moles

Thus, the moles of H⁺ you need to add are:

0,265 - 1,24x10⁻³ = <em>0,26376 moles</em>

These moles comes from 10M HCl, thus, the volume in gallons you need to add are:

0,26376moles*\frac{1L}{10moles}* \frac{1gallon}{3,78541L} =

<em>6,97x10⁻³ gallons</em>

<em></em>

I hope it helps!

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