The sum of the m numbers divided by m (which is the average) equals n^2. Then, the sum of the m numbers equals mn^2.
The sum of the n numbers divided by n (which is the average) equals m^2. Then, the sum of the n numbers equals nm^2.
The average of m+n numbers which is the sum of the m numbers plus the sum of the n numbers divided by (m+n) equals (mn^2+nm^2)/(m+n). This is mn(n+m)/(m+n). Then the factor (m+n) can be ruled out and the result is mn.
Given:
w be the weight in pounds of a baby tigers.
To find:
The inequality if baby tigers can be no larger than 4 pounds.
Solution:
Baby tigers can be no larger than 4 pounds. It mean weight of baby tigers cannot be greater than 4. In other words, the weight of the baby tigers must be less than or equal to 4.
Let w represents weight in pounds and the weight of the baby tigers must be less than or equal to 4. So,

Therefore, the required inequality is
.
Answer:
0.15% decrease
Step-by-step explanation:
18.75 - 18.60 = 0.15
Hope this helped!