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2 years ago

Evaluate the question below . 12-2

Mathematics

1 answer:

MAXImum [283]2 years ago

8 0

Answer:

=>12-2

=> 10

<em><u>You're Welcome</u></em>

<em><u>Hope this helps you.</u></em>

<h2><em><u>Pls</u></em><em><u>, mark it as the brainliest. I need it.</u></em></h2>

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Marcus wants to use a model to determine the difference

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We want to see how we can model the difference: -8 - 3 + 3

The correct option is D:

"add 3 positive counters and 3 negative counters"

We know that Marcus starts with 8 negative counters, corresponding to the first term in our difference.

Now, let's study the math of our expression.

-8 - 3 + 3

Remember that we can perform the operation in any order we want, so we can write this as:

-8 + (-3 + 3)

Notice that the thing inside the parentheses is equal to zero, so we have:

- 8 + (-3 + 3) = -8

So to not change the value, we add 3 and we subtract 3.

Now if we have 8 negative counters, and we want to add 3 positive counters and not change the value, then we also need to add 3 negative counters to "cancel" the 3 positive counters we added.

Then the correct option is D.

To learn more about Marcus refer to,

brainly.com/question/23140234

#SPJ1

8 0

8 months ago

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

1 year ago

PLZ HELP WORTH EXTRA POINTS!!<br> 3D pythagream theroem!

Alja [10]

Answer:

$\sqrt{69}$

Step-by-step explanation:

6 0

2 years ago

Tommy purchased a riding lawnmower with an original value of $2,500. If the value of the riding lawnmower decreases by $300 per

Eva8 [605]

Answer:

$1000.

Step-by-step explanation:

Let x represent number of years.

We have been given that Tommy purchased a riding lawnmower with an original value of $2,500. The value of the riding lawnmower decreases by $300 per year. We are asked to find the value of lawnmower after 5 years.

Since the value of the riding lawnmower decreases by $300 per year, so value of lawnmower decrease in 5 years would be 5 times $300.

The final value of lawnmower would be initial value minus value decreased in 5 years.

$\text{The value of the lawnmower after five years}=\$2500-\$300(5)$