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3 years ago

Lily estimated a quotient of 120 and found an actual quotient of 83 what should she do next

1 answer:

8 0

She should go back to her problem solving, determine whether or not a mistake was made, & redo the problem, if necessary.

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Which equation represents the solution of the equation 6x - 18 = 30?

defon

Answer:

x=8

Step-by-step explanation:

firstly take 30+18 which equals 48 and then divide that by six which will give you 8 as your answer

7 0

2 years ago

Read 2 more answers

20. What is the volume, in terms of r, for a cylindrical

inysia [295]

Step-by-step explanation:

Volume of cylindrical container

$= \pi {r}^{2} h \\ \\ = 3.14 \times ( {3.25)}^{2} \times 10 \\ \\ = 3.14 \times 10.5625 \times 10 \\ \\ = 331.6625 {cm}^{3} \\ \\ \approx \: 331.66 \: {cm}^{3}$

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3 years ago

A square has a perimeter of 16.4 inches. The<br> area of the square is<br> square inches.

slamgirl [31]

Answer:

area = 8.2 sq inch

Step-by-step explanation:

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2 years ago

The step function f of x is graphed what is the value of f of 0?

zzz [600]

Answer:

AYYYYYYYYYYYY YO IS SNOOP DOGG

Step-by-step explanation:

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3 years ago

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Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$