What is the value of d/dx (6/x^4 + 1/x^2) at x = -1 ?

1 answer:

7 0

Answer:

\frac{d}{dx}\left(\frac{1+x^4+x^6}{x^2+x+1}\right)=\frac{4x^7+5x^6+8x^5+3x^4+4x^3-2x-1}{\left(x^2+x+1\right)^2}

Step-by-step explanation:

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