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seropon [69]
3 years ago
10

The quadratic function f (x) = - 45x2 + 350x + 1,590 models the population of a city where x represents the number of years sinc

e 2005 and f (x) is the population of the city in thousands of people. What is the estimated population of the city in 2010?
Mathematics
1 answer:
kramer3 years ago
3 0

Answer: 2,215,000

Step-by-step explanation:

Given: The quadratic function f (x) = - 45x^2 + 350x + 1,590 models the population of a city where x represents the number of years since 2005.

To Find:  population of the city in 2010

We need to put x= 2010-2005 = 5

f (5) = - 45(5)^2 + 350(5) + 1,590\\\\=-1125+1750+1590 =2215

Hence, the estimated population of the city in 201 = 2215 thousands or 2,215,000 .

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Serena uses chalk to draw a straight line on the sidewalk. The line is 12 ft long. She wants to divide the line into sections th
ElenaW [278]
<h3><u>Question:</u></h3>

Serena uses chalk to draw a straight line on the sidewalk. The line is 1/2 ft long. She wants to divide the line into sections that are each 1/8 ft long. How many sections will the line be divided into?

<h3><u>Answer:</u></h3>

The number of sections that the line is divided is 4

<h3><u>Solution:</u></h3>

Given that, Serena uses chalk to draw a straight line on the sidewalk

The line is 1/2 ft long. She wants to divide the line into sections that are each 1/8 ft long

From given,

Total\ length\ of\ line = \frac{1}{2} \text{ feet }\\\\Length\ of\ each\ section = \frac{1}{8} \text{ feet }

To find: Number of sections can be made

The number of sections that can be made is found by dividing the total length of line by length of each section

\text{Number of sections } = \frac{\text{Total length of line}}{\text{length of each section}}

Substituting the values, we get,

\text{Number of sections } = \frac{\frac{1}{2}}{\frac{1}{8}}\\\\\text{Number of sections } = \frac{1}{2} \times \frac{8}{1}\\\\\text{Number of sections } = 4

Thus number of sections that the line is divided is 4

8 0
3 years ago
The number 18 is which % of 15
Anuta_ua [19.1K]
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Find the 9th term of the geometric sequence whose common ratio is 1/3 and whose first term is 2.
raketka [301]

Answer:

2/6561

Step-by-step explanation:

Geometric sequence formula : a_n=a_1(r)^n^-^1

where an = nth term, a1 = first term , r = common ratio and n = term position

given ratio : 1/3 , first term : 2 , given this we want to find the 9th term

to do so we simply plug in what we are given into the formula

recall formula : a_n=a_1(r)^n^-^1

define variables : a1 = 2 , r = 1/3 , n = 9

plug in values

a9 = 2(1/3)^(9-1)

subtract exponents

a9 = 2(1/3)^8

evaluate exponent

a9 = 2 (1/6561)

multiply 2 and 1/6561

a9 = 2/6561

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2 years ago
PLEASE HELP!!!
Brut [27]

Answer:PLEASE HELP!!!

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