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UNO [17]
4 years ago
13

Liability insurance covers bodily injury to others and any property damaged, including yours.

Mathematics
2 answers:
ehidna [41]4 years ago
4 0
False, it only covers the other persons damages. That's what makes you "liable"
SSSSS [86.1K]4 years ago
3 0

Liability insurance covers bodily injury to others and any property damaged, including yours. This statement is TRUE.

There are several types of liability insurance. Auto liability insurance covers the damages that you've created to someone else's car and bodily injury.

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Ganezh [65]

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of what tho

Step-by-step explanation:

6 0
3 years ago
PAIesung
Svetllana [295]

Answer:

The sale price was 60% of the purchase price.

Step-by-step explanation:

Given that Blake bought a motorcycle for $ 550 last year and sold it for $ 330 this year, to determine what is his sale price as a percentage of his purchase price, the following calculation must be performed:

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Therefore, the sale price was 60% of the purchase price.

5 0
3 years ago
9. Write the slope-intercept form of the equation of the line through the given points. Write answer as y=mx+b. through: (-4, 5)
densk [106]

Answer:

y = -x + 1

Step-by-step explanation:

(-4,5) (1,0)

Find distance through a number line.

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(5,-5)

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-5/5

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-1/1 or -1

To find the y-intercept get x to be at zero and see where y ends. Let's use the point (1,0):

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= (0,1)

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3 0
3 years ago
Read 2 more answers
2.4n + 1.2n - 0.12 = 7.08
Basile [38]

Answer:

n=2

Step-by-step explanation:

7 0
3 years ago
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Prove the theorem (AB )^T= B^T. A^T
Lisa [10]

Answer:

(AB)^T = B^T.A^T  (Proved)

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Given  (AB )^T= B^T. A^T;

To prove this expression, we need to apply multiplication law, power law and division law of indices respectively, as shown below.

(AB)^T = B^T.A^T\\\\Start, from \ Right \ hand \ side\\\\B^T.A^T = \frac{B^T.A^T}{A^T}.\frac{B^T.A^T}{B^T} (multiply \ through) \\\\                = \frac{A^{2T}.B^{2T}}{A^T.B^T} \\\\=\frac{(AB)^{2T}}{(AB)^T} \ \ (factor \ out \ the power)\\\\= (AB)^{2T-T}  \ (apply \ division \ law \ of \ indices; \ \frac{x^a}{x^b} = x^{a-b})\\\\= (AB)^T \ (Proved)

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3 years ago
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