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Natasha_Volkova [10]
3 years ago
14

The solution set for all real numbers x such that 2x + 3 < 19 and 2x − 3 ≤ -7 is (blank, blank]

Mathematics
1 answer:
fgiga [73]3 years ago
3 0
Hello : 
<span>2x + 3 < 19 and 2x − 3 ≤ -7 :
the system :
</span><span>2x + 3 < 19 .....(1)
2x − 3 ≤ -7......(2)
by (1) : 2x </span>< 16
             x < 8
by(2) : 2x  ≤ -4
           x ≤ -2
conclusion :   x < 8 and  x ≤ -2
The solution set  is : x ≤ -2
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Zigmanuir [339]

\huge \pink{solution}

Given :7x+6=5(x+2)

Now We will use the distributive property to multiply 5 by x+2.

→7x+6=5x+10

We will Subtract 5x from both sides.

→7x+6−5x=10

We will Combine 7x and −5x to get 2x.

→2x+6=10

We will Subtract 6 from both sides.

2x=10−6

We will Subtract 6 from 10 to get 4.

2x=4

We will Divide both sides by 2.

x= 4/2

At last,We Divide 4 by 2 to get 2.

x=2

7 0
3 years ago
Read 2 more answers
P(x) = 2x^3+5x -19 if x=2
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I think the answer is 2p = 7
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2 years ago
What is the amount, base, and percent in the expression.
Illusion [34]

Answer:

The correct answer is :

Amount: 2

Base: 100

Percent: 2%

Step-by-step explanation:

So, we get the answer by using whatever we know. The first step is that 2 is the percent because it is having the percent sign . In addition we know that 100 is the base. And the one which is left is 2 so it's the amount.

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Your answer is 12 :)
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3 years ago
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Which expression is equivalent to (4x^(3)y^(5))(3x^(5)y)^(2)
marshall27 [118]

Answer:

(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7

Step-by-step explanation:

Given

(4x^3y^5)(3x^5y)^2

Required

The equivalent expression

We have:

(4x^3y^5)(3x^5y)^2

Expand

(4x^3y^5)(3x^5y)^2 = 4x^3y^5*9x^{10}y^2

Further expand

(4x^3y^5)(3x^5y)^2 = 4*9*x^3*x^{10}y^5*y^2

Apply laws of indices

(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7

8 0
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