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3 years ago

8

Photon the polar bear and Peanut the penguin are playing on a sea saw that is 5.0m long from center of seat to center of seat. W

hat is the force of gravity between Photon and Peanut. Use your equation card for the equation and constant.
Photon has a mass of 250.0kg

Peanut has a mass of 7.0kg.

1 answer:

wel3 years ago

5 0

You're going to want to use F=G(m1m2/d^2)
the gravitational constant(G) is 6.67x10^-11
so:
F=(6.67x10^-11)*((250.00kg*7.0kg)/(5.0kg)^2)
and you should get F=466.9x10^-9

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Step-by-step explanation:

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Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

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Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

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Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

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